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4 years ago

8 plus 4 times a number is greater than 5 times the number

Mathematics

2 answers:

Sliva [168]4 years ago

8 0

Answer:

x<8

Step-by-step explanation:

4x+8>5x

8>5x-4x

8>x

Bas_tet [7]4 years ago

7 0

The answer would be 4x+8>5x

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A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in

SashulF [63]

Answer:

The number of machines to complete job in 2 hours is 6.

Step-by-step explanation:

Using the relation of the rate of each one machine and knowing that adding up both rates.

$Rate R +Rate S= Rate total$

Rate R = $\frac{x}{36}$ 'x' is the job

Rate S = $\frac{x}{18}$ 'x' is the job

So, using the equation of rates

$Rate total =\frac{x}{36} + \frac{x}{18}$

Rate total is going to be a job in 2 hours so = $\frac{1}{2}$

$\frac{1}{2} = \frac{x}{36}+\frac{x}{18}$ <em>adding up</em>

$\frac{1}{2}= x*\frac{3}{36}$ <em>factoring the x</em>

$\frac{1}{2}= x*\frac{1}{12}$ <em>simplifying</em>

x= $\frac{12}{2} \\$

x= 6

3 0

3 years ago

The average temperatures for two of the world's hottest places are given. Determine which location has the warmer average temper

zubka84 [21]

Answer: City A, $0.28^{\circ}C$

Step-by-step explanation:

Given

The temperature of city A is $86.7\ ^{\circ}F$

The temperature of city B is $30.1^{\circ}C$

We know, $32^{\circ}F=0^{\circ}C$

So, $86.7^{\circ}F=30.38^{\circ}C$

$30.38>30.1$

Clearly, the average temperature of city A is more than city B

The difference in temperature is $30.38-30.1=0.28^{\circ}C$

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3 years ago

0.35(j + 5) − 5.77 = –2.97<br> What does the j = ?<br> Also explain how you got the answer

Kruka [31]

Answer:

Step-by-step explanation:

got the answer, attached is drawn

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3 years ago

assume the age of night school students is normally distributed. A simple random sample of 24 night school students had an avera

aleksley [76]

Let
n = number of data
s = standard deviation (sample)
S = standard deviation (population)

The working equations is

$\frac{(n-1) s^{2} }{ x^{2}_{right} } \ \textless \ S^{2} \ \textless \ \frac{(n-1) s^{2} }{ x^{2}_{left} }$

To find $x^{2}_{right}$ , : (1 - 0.90)/2 = 0.05

To find $x^{2}_{left}$ , : 1 - 0.05 = 0.95

Degrees of freedom = n-1 = 24 - 1 = 23

This is shown in the figure attached. Since there is no row for df=23, we interpolate. Thus,

$x^{2}_{left} = 13.093$

$x^{2}_{right} = 35.17$

Substitute all values,

$\frac{(24-1) 5.6^{2} }{ 35.17} \ \textless \ S^{2} \ \textless \ \frac{(24-1) 5.6^{2} }{ 13.093} }$

Thus the answer is,

$20.51\ \textless \ S^{2} \ \textless \ 55.09$

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3 years ago

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nlexa [21]

Answer: 26/50

Step-by-step explanation:

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3 years ago