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Mrrafil [7]
4 years ago
14

Determine the enthalpy change when 19.399999999999999 g of carbon is reacted with oxygen according to the reaction

Chemistry
1 answer:
Flauer [41]4 years ago
8 0

Answer:

The enthalpy change is −636.9798 kJ

Explanation:

The equation of the reaction between Carbon and Oxygen can be represented as :

C_{(s)} + O_{2(g)} \to CO_{2_(g)} \ \ \ \  \  \ \Delta H  = -394 \ \ kJ/mol

molar mass of Carbon = 12 mole

when mass of  19.399999999999999 g of carbon reacted with oxygen;

the number of moles = mass/molar mass

the number of moles = 19.399999999999999/12

the number of moles = 1.6167 mol

Thus the enthalpy change when  1 mole of carbon react with oxygen = -394 kJ/mol

Therefore when 1.6167 moles react with oxygen; we have:

= 1.6167 mol ×  -394 kJ/mol

= −636.9798 kJ

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Calculate the concentration of acetic acid, HAc, and acetate ion, Ac−, in a 0.25M acetate buffer solution with pH = 5.36. "0.25M
Neporo4naja [7]

Answer:

[HAc] = 0.05M

[Ac⁻] = 0.20M

Explanation:

The Henderson-Hasselbalch formula for the acetic acid buffer is:

pH = pka + log₁₀ [Ac⁻] / [HAc]

Replacing:

5.36 = 4.76 + log₁₀ [Ac⁻] / [HAc]

3.981 = [Ac⁻] / [HAc] <em>(1)</em>

Also, as total concentration of buffer is 0.25M it is possible to write:

0.25M =  [Ac⁻] + [HAc] <em>(2)</em>

Replacing (2) in (1)

3.981 = 0.25M - [HAc] / [HAc]

3.981 [HAc] = 0.25M - [HAc]

4.981 [HAc] = 0.25M

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Replacing this value in (2):

0.25M =  [Ac⁻] + 0.05M

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7 0
4 years ago
2. 2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
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Answer:

84.4g of AgCl

Explanation:

Based on the reaction:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂

<em>2 moles of AgNO₃ and 1 mole of CaCl₂ priduce 2 moles of AgCl and 1 mole of Ca(NO₃)₂</em>

<em />

100g of each reactant are:

AgNO₃: 100g × (1mol / 169.87g) = 0.589 moles

CaCl₂: 100g × (1mol / 110.98g) = 0.901 moles

For a complete reaction of 0.901 moles of CaCl₂ are necessaries 0.901×2 = <em>1.802 moles of AgNO₃. </em>As there are just 0.589moles, <em>AgNO₃ is limitng reactant</em>

<em></em>

0.589 moles of AgNO₃ produce:

0.589 moles × ( 2 moles AgCl / 2 moles AgNO₃) =

<em>0.589 moles of AgC</em>l. In mass:

0.589 moles of AgCl × (143.32g / mol) =<em> 84.4g of AgCl</em>

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