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Nitella [24]
3 years ago
7

The are of a rectangle is 12 in^2. what is the area in cm^2. there are 2.54cm in an inch.

Chemistry
1 answer:
balu736 [363]3 years ago
6 0
Area measured in squares (or square units). We can count the squares or we can take the length and the width multiplication. The rectangle above has an area of 15 square units.
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Please help me due today at 7:00pm please help giving more points please help me
kkurt [141]
The answer is 20N as when the object is accelerating at 3 m/s2 it as a force of 10N applied to it so to get to 6m/s2 3(x2) = 6 so 10(x2) = 20
6 0
3 years ago
Determine the number of protons, neutrons, and electrons for a neutral potassium-41 isotope.
Sphinxa [80]


Atomic number is equal to the number of electrons in a neutral atom. ... Niobium has an atomic number of 41. ... Determine the number of protons, electrons, and neutrons for each isotope described ... Potassium-41. 19
6 0
3 years ago
A mixture of XO2 (P = 3.00 atm) and O2 (P = 1.00 atm) is placed in a container. This elementary reaction takes place at 27 °C: 2
sukhopar [10]

Answer:

a) \triangle G^{0} = 7.31 kJ/mol

b) K_{-1} = 0.0594 m^{-1} s^{-1}

Explanation:

Equation of reaction:

                                     2 XO_{2} (g) + O_{2} (g) \rightleftharpoons 2XO_{3} (g)

Initial pressure                  3              1              0

Pressure change             2P           1P             2P

Total pressure = (3-2P) + (1-P) + (2P)

Total Pressure = 3.75 atm

(3-2P) + (1-P) + (2P) = 3.75

4 - P = 3.75

P = 4 - 3.75

P = 0.25 atm

Let us calculate the pressure of each of the components of the reaction:

Pressure of XO2 = 3 - 2P = 3 - 2(0.25)

Pressure of XO2 =2.5 atm

Pressure of O2 = 1 - P = 1 -0.25

Pressure of O2 = 0.75 atm

Pressure of XO3 = 2P = 2 * 0.25

Pressure of XO3 = 0.5 atm

From the reaction, equilibrium constant can be calculated using the formula:

K_{p} = \frac{[PXO_{3}] ^{2} }{[PXO_{2}] ^{2}[PO_{2}] }

K_{p} = \frac{0.5^2}{2.5^2 *0.75} \\K_{p} = 0.0533 = K_{eq}

Standard free energy:

\triangle G^{0} = - RT ln k_{eq} \\\triangle G^{0} = -(0.008314*300* ln0.0533)\\\triangle G^{0} = 7.31 kJ/mol

b) value of k−1 at 27 °C, i.e. 300K

K_{1} = 7.8 * 10^{-2} m^{-2} s^{-1}

K_{c} = K_{p}RT\\K_{c} = 0.0533* 0.0821 * 300\\K_{c} = 1.313 m^{-1}

K_{-1} = \frac{K_{1} }{K_{c} } \\K_{-1} = \frac{7.8 * 10^{-2}  }{1.313 }\\K_{-1} = 0.0594 m^{-1} s^{-1}

6 0
3 years ago
In the metric system of units (S.I), the basic unit of length is ___?
myrzilka [38]

Answer:

meters

Explanation:

6 0
2 years ago
how many formula units of CaCl2 are in 111 g CaCl2? the molar mass of calcium chloride is about 111 g/mol
d1i1m1o1n [39]

There are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2. Details about formula units can be found below.

<h3>What is a formula unit?</h3>

Formula unit refers to the empirical formula of an ionic compound for use in stoichiometric calculations.

According to this question, there are 111g of CaCl2. The formula units can be calculated by multiplying the number of moles by Avogadro's number.

no of moles in CaCl2 = 111g ÷ 111g/mol = 1mol

Formula units of CaCl2 = 1mol × 6.02 × 10²³ = 6.02 × 10²³ formula units.

Therefore, there are 6.02 × 10²³ formula units of CaCl2 in 111 g CaCl2.

Learn more about formula units at: brainly.com/question/21494857

#SPJ1

5 0
1 year ago
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