Answer:
The correct answer is - B. dissolving → evaporation filtration → crystallisation
Explanation:
The method of the preparation of a pure sample of copper(II) sulfate from dilute sulfuric acid and copper II oxide is given as follows:
step 1. Adding dilute sulfuric acid into a beaker. Using bunsen burner heat the beaker.
step 2. Adding the copper (II) oxide into the beaker and give it a little time at a time to the warm dilute sulfuric acid and stir
step 3. Filtering the mixture into an evaporating vessel to remove the excess copper (II) oxide and water from the filtrate.
Step 4. leave the rest filtrate to crystallize.
Copper (II) Oxide {CuO (s)} + Dilute Sulfuric Acid {H2SO4 (aq)} → Copper (II) Sulphate {CuSO4 (s)} + Water {H2O}
Answer:
3 to 5
Explanation:
The pH scale is from 0 to 14.
Acids have a pH of anything less than 7.
Anything with a pH greater than 7 is considered to be a base.
If a solution has a pH of 7, it is neutral.
3 to 5 is in the range of less than 7, so a solution of an acid can have this pH.
6 to 8 includes less than 7 , 7 and greater than 7, so it is not just in the range of an acid.
9 to 11 and 12 to 14 are both in the range of greater than 7, so they have to be bases.
Therefore, the correct answer is 3 to 5.
Answer:
Ethanol is completely miscible due to <u><em>presence</em></u> of Hydrogen bonding.
Ethanethiol is partially miscible due to <u><em>absence</em></u> of Hydrogen Bonding.
Explanation:
The miscibility of liquids depend upon the intermolecular interactions between the two liquids. The stronger the intermolecular interactions the more miscible will be the liquids.
Among the two given examples, Ethanol is more miscible in water because it exhibits hydrogen bonding which is considered the strongest intermolecular interaction. Hydrogen bonding occurs when the hydrogen atom is bonded to more electronegative atoms like Fluorine, Oxygen and Nitrogen. In this way the hydrogen atom gets partial positive charge and the electronegative atom gets partial negative charge. Hence, these partial charges results in attracting the opposite charges on other surrounding atoms.
While, in case of Ethanethiol the hydrogen atom is not bonded to any high electronegative atom hence, there will be no hydrogen bonding and therefore, there will be less interactions between the neighbour atoms.
