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4 years ago

2. 2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2

Chemistry

1 answer:

Slav-nsk [51]4 years ago

3 0

Answer:

84.4g of AgCl

Explanation:

Based on the reaction:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂

2 moles of AgNO₃ and 1 mole of CaCl₂ priduce 2 moles of AgCl and 1 mole of Ca(NO₃)₂

100g of each reactant are:

AgNO₃: 100g × (1mol / 169.87g) = 0.589 moles

CaCl₂: 100g × (1mol / 110.98g) = 0.901 moles

For a complete reaction of 0.901 moles of CaCl₂ are necessaries 0.901×2 = 1.802 moles of AgNO₃. As there are just 0.589moles, AgNO₃ is limitng reactant

0.589 moles of AgNO₃ produce:

0.589 moles × ( 2 moles AgCl / 2 moles AgNO₃) =

0.589 moles of AgCl. In mass:

0.589 moles of AgCl × (143.32g / mol) = 84.4g of AgCl

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