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BARSIC [14]
3 years ago
5

the Royal fruit company produces two types of fruit drinks. The first type is 20% pure fruit juice, and the second type is a 45%

pure fruit juice. the company is attempting to produce a fruit drink that contains 35% pure fruit juice. how many pints of each of the two existing types of drinks must be used to make 30 pints of a mixture that is 35% pure fruit juice ?
Mathematics
1 answer:
AlexFokin [52]3 years ago
6 0

We know that 20% of the first type of juice is pure fruit juice and 45% of second type of juice is pure fruit juice.

Now we have to make 30 pints of a mixture that is 35% pure.

Let x be the number of pints of first type of juice and y be the number of pints of second type of juice.

So, x+y=30 (Equation 1)

Since, 20% of x + 45% of y = 35.3% of 30

\frac{x}{5}+\frac{9y}{20}=10.5 (Equation 2)

Solving equations 1 and 2,

we get y=18 and x=12.

So, 12 pints of first type of juice and 18 pints of second type of juice are used.

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The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0
1 year ago
Well my question is whats -4-(-5+5)
Mnenie [13.5K]
First lets figure out what -5+5 equals. so -5+5=0. so then -4-0 equals -4. so therefor your answer is -4
4 0
3 years ago
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How do you find the surface area of a cube?
timofeeve [1]
You find the surface area of a cube by using A=6a^2
8 0
2 years ago
The relative frequency approach to probability uses long term relative frequencies, often based on past data.
xenn [34]

Answer:

True

Step-by-step explanation:

Relative frequency is the ratio of the occurrence of a singular event and the total number of outcomes. This is a tool that is often used after you collect data. You can compare a single part of the data to the total amount of data collected.

For example, if a particular machine produces 50,000 widgets one at a time, and 5,000 of those widgets are faulty, the probability of that machine producing a faulty widget is approximately 5,000 out of 50,000, or 0.10.

4 0
3 years ago
Can anyone help me please 3t-1/4=7/8
julsineya [31]
3t − 1/4 = 7/8

Add 1/4 to both sides.

3t + −1/4 + 1/4 = 7/8 + 1/4

3t = 9/8

Divide both sides by 3.

3t/3 = 98/3

t=3/8

3 0
3 years ago
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