Find an equation for the line tangent to the circle x^2 +y^2=25 at the point (3, -4)
1 answer:
You might be interested in
Answer:
1. x=3 x=1
2. x=0
Step-by-step explanation:
We want f(x) to equal g(x)
f(x)=g(x)
1/(x-2) = (x-2)
Using cross products
1 = (x-2) * (x-2)
1 = x^2 -2x-2x+4
Subtract 1 from each side
1-1 = ^2 -2x-2x+4-1
0 = x^2 -4x+3
Factoring
What number multiplies to 3 and adds to -4
-3*-1 = 3
-3+-1 = -4
0= (x-3) (x-1)
Using the zero product property
x-3 =0 x-1=0
x=3 x=1
2. f(x)=x^2+4x+2
g(x)=(1/2)^ x+1
From the graph,we can see they intersect at x=0
The necessary formulas to get the area of a circle’s segment are the area of the circle’s sector and the triangle it is bounded by.
Hence the formula for the segment’s area is:Area of Segment = Area of sector – area of the triangle.
The formula of the area of a circle’s sector is:Area of Sector =
x (radius of circle)²
While the formula for the area of a triangle is:Area of Triangle =
x base of triangle x height of triangle
Hence the formula for the segment’s area is:Area of Segment = Area of sector – area of the triangle.
The formula of the area of a circle’s sector is:Area of Sector =
While the formula for the area of a triangle is:Area of Triangle =