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Svetlanka [38]
3 years ago
6

Which is the formula for diarsenic pentoxide?

Chemistry
1 answer:
gladu [14]3 years ago
6 0

As205

Hope this helps:)

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The reactant atoms are copper, hydrogen, nitrogen, and oxygen. Which reactant atom was oxidized in the reaction?
SCORPION-xisa [38]

Answer:

C. copper.

Explanation:

  • The atom which loses electrons (its oxidation sate be more positive) is the atom that is oxidized.
  • While, the atom which gains electrons (its oxidation sate be more negative) is the atom that is reduced.

  • Nitrogen:

It is oxidation sate is changed from (+5) in the reactants (NO₃⁻) to (+4) in the products (NO₂). N gains 1 electron

So, it is reduced.

  • Oxygen:

It is oxidation sate is the same (-2) in the reactants (NO₃⁻) and (-2) in the products (NO₂).

<em>So, it is neither be oxidized nor reduced.</em>

<em></em>

  • Copper:

It is oxidation sate is changed (0) in the reactants (Cu) to (+2) in the products (Cu²⁺). Cu loses 2 electrons.

<em>So, it is oxidized.</em>

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  • Hydrogen:

It is oxidation sate is the same (+1) in the reactants (H⁺) and (+1) in the products (H₂O).

<em>So, it is neither be oxidized nor reduced.</em>

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4 years ago
Write correctly a balanced equation for the following "word" equation: Red lead → lead monoxide + oxygen​
Nat2105 [25]

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Baking soda has a pH of 8. Its a(n) _________ substance
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3 years ago
Perform the following operation
Paul [167]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:2.8 × {10}^{-5}

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  \dfrac{2.36 \times 10 {}^{ - 2} }{8.4  \times {10}^{2} }

\qquad \tt \rightarrow \:  \dfrac{2.36  }{8.4   } \times  \cfrac{10 {}^{ - 2} }{10 {}^{2} }

\qquad \tt \rightarrow \:  0.28 \times 10 {}^{ - 2 - 2}

\qquad \tt \rightarrow \:  0.28  \times 10 {}^{  - 4}

\qquad \tt \rightarrow \: 2.8 \times 10 {}^{ - 5}

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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If you are titrating a base into an acid (adding base to acid) what color
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