Answer:
38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.
Explanation:
Mass of acetanilide to be dissolved in hot water = 2.1 g
Mass of hot water to be used = m
Solubility of acetanilide = 55 g/L
This means that 55 grams of acetanilide dissolves in 1 L of hot water.
Then 1 grams of acetanilide will dissolve in :

0.0382 L = 0.0382 × 1000 mL =38.2 mL
1 L = 1000 mL
38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.
Answer:
10.1g of H₂ are produced
Explanation:
To solve this question we need, first, to convert the mass of each reactant to moles and, using the chemical reaction, find limiting reactant. With limiting reactant we can find the moles of H2 and its mass:
<em>Moles Zn -Molar mass: 65.38g/mol-:</em>
307g * (1mol / 65.38g) = 4.696 moles
<em>Moles HCl -Molar mass: 36.46g/mol-:</em>
381g HCl * (1mol / 36.46g) = 10.45 moles
For a complete reaction of 10.45 moles of HCl are required:
10.45 moles HCl * (1mol Zn / 2mol HCl) = 5.22 moles Zn
As there are 4.696 moles of Zn, <em>Zn is the limiting reactant</em>
<em />
The moles of H₂ produced = Moles of Zn added = 4.696 moles. The mass is-Molar mass H₂ = 2.16g/mol-:
4.696 moles * (2.16g / mol) =
<h3>10.1g of H₂ are produced</h3>
Answer:
[Co(H₂O)₆]²⁺ = 0.361 M
Explanation:
[CoCl₂ . 6H₂O] + 2Cl⁻ → [CoCl₄]²⁻ + 6H₂O
[Co(H₂O)₆]²⁺ + 4Cl⁻ → [CoCl₄]²⁻ + 6H₂O
[CoCl₄]²⁻ = 0.361 M ∴ [Co(H₂O)₆]²⁺ = 0.361 M
The equation shows that the concentration of [Co(H₂O)₆]²⁺ should be equal to the concentration of [CoCl₄]²⁻.
The particles in a solid are tightly packed and locked in place. Although we cannot see it or feel it, the particles are vibrating in place.
As these molecules heat up, they will vibrate more vigorously, and will eventually turn to water, then gas.
I think it will stay the same.