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qwelly [4]
3 years ago
14

Greatest common factor of five ​

Mathematics
1 answer:
arsen [322]3 years ago
6 0

Answer:

GCF(greatest common factor) of 5 is 5.

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75 points! Will mark brainliest! Only answer if you know it! Random answers will be reports because I’m trying to get the true r
Anna [14]

Answer:

y=1/2x

Step-by-step explanation:

Find the slope of the original line and use the point-slope formula y−y1=m(x−x1) to find the line parallel to y=1/2x−8

I know this isn't much but please don't report me. I got this answer ):

6 0
3 years ago
Please Explain/Show Your Work, for each part of the question! Thank You!
mina [271]

Answer:

1. The graph represents a proportional relationship

2. 70,000 miles

Step-by-step explanation:

1. The graph represents a proportional relationship since the graph line is straight and begins at the origin.

2. Plot 5.5 hours on the graph and it'll give you 70,000 miles

3 0
3 years ago
an elevator can carry 800 of weight. A football player weighting 280 pounds gets on the elevator with a student. Write and solve
Nesterboy [21]

Answer:

425\geq x

425 pounds or less can be added after the student and football player.

Step-by-step explanation:

let x = remaining weight

(note that >/= is greater than or equal to.)

800 - 280 - 95 >/= x

425 >/= x

8 0
2 years ago
Please answer these I will give you all my points!
makvit [3.9K]
  1. 300
  2. 59
  3. 4
  4. 78

ok so put it like that and it will be correct.............................................................................(long pause)........................................................................................................... (thinks) I think that the right answer.

5 0
3 years ago
A University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A s
Alla [95]

Answer:

The point estimate for this problem is 0.48.

Step-by-step explanation:

We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.

A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".

<em>Let </em>\hat p<em> = proportion of students who felt comfortable reporting cheating by their fellow students</em>

<u></u>

<u>Now,  point estimate (</u>\hat p<u>) is calculated as;</u>

                               \hat p=\frac{X}{n}

where, X = number of students who answered yes = 1,344

            n = number of students surveyed = 2,800

So, Point estimate (\hat p)  =  \frac{1,344}{2,800}

                                     =  <u>0.48 or 48%</u>

5 0
3 years ago
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