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katen-ka-za [31]
4 years ago
14

Find three mixed numbers so that the sum is 18 and the difference between the greatest number and least number is 5 1/5

Mathematics
1 answer:
Zigmanuir [339]4 years ago
7 0
Suppose y=0. That means 
<span>x+z = 18 </span>
<span>x-z = 26/5 </span>

<span>x = 58/5 </span>
<span>z = 32/5 </span>

<span>So, the largest x can be is 58/5 </span>
<span>Now, suppose we toss in y. If we subtract y/2 from both x and z, then the difference between x and z is still 26/5, and the sum is </span>

<span>(x-y/2) + y + (z-y/2) = x+z = 18 </span>

<span>For example, if y = 4, </span>

<span>x = 48/5 </span>
<span>y = 20/5 </span>
<span>z = 22/5 </span>

<span>x-z is still 26/5, and the sum is still 18. </span>
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square root both sides
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You start at (1, 0). You move up 4 units and down 2 units. Where do you end?
melisa1 [442]

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(1, 2)

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Liam had 250. Then, he and his classmates bought a present for their teacher, evenly splitting the 120 cost among the e of them.
vodomira [7]
The number of children who contribute toward the present is represented as 'e'

The cost of the present is 120 and the children split the cost evenly between them. The expression for this is \frac{120}{e}

Liam has to give \frac{120}{e} towards the present

Liam has 250 with him

If he gives \frac{120}{e} away, then the money he has left is:

250- \frac{120}{e}
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Given:
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term = 3 years

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