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katen-ka-za [31]
3 years ago
14

Find three mixed numbers so that the sum is 18 and the difference between the greatest number and least number is 5 1/5

Mathematics
1 answer:
Zigmanuir [339]3 years ago
7 0
Suppose y=0. That means 
<span>x+z = 18 </span>
<span>x-z = 26/5 </span>

<span>x = 58/5 </span>
<span>z = 32/5 </span>

<span>So, the largest x can be is 58/5 </span>
<span>Now, suppose we toss in y. If we subtract y/2 from both x and z, then the difference between x and z is still 26/5, and the sum is </span>

<span>(x-y/2) + y + (z-y/2) = x+z = 18 </span>

<span>For example, if y = 4, </span>

<span>x = 48/5 </span>
<span>y = 20/5 </span>
<span>z = 22/5 </span>

<span>x-z is still 26/5, and the sum is still 18. </span>
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