Answer:
The length of segment DA is 15 units
Step-by-step explanation:
- <em>The segment which joining a vertex of a triangle and the midpoint of the opposite side to this vertex is called a median </em>
- <em>The point of intersection of the median of a triangle divides each median into two parts the ratio between them is 1: 2 from the base, which means </em><em>the length of the median is 3 times the part from the base</em><em> </em>
Let us use this rule to solve the question
In Δ AEC
∵ D is the midpoint of EC
∴ AD is a median
∵ B is the midpoint of AC
∴ EB is a median
∵ F is the midpoint of AE
∴ CF is a median
→ The three medians intersected at a point inside the triangle,
let us called it M
∵ AD ∩ EB ∩ CF at M
∴ M is the point of intersection of the medians of Δ AEC
→ By using the rule above
∴ AD = 3 MD
∵ MD = 5
∴ AD = 3(5)
∴ AD = 15 units
Answer:
B
Step-by-step explanation:
The second graph is the correct choice because the y-intercept is two, the graph is negative, and has a slope of m=3/1.
-1
In a slope intercept equation, y=mx+b B is always the Y intercept
Twice the sum of a number and 4 is 14. In this case the numbers are added first, and the ANSWER is doubled.
The equation is in standard form. Standard form is in this formula:
Ax + By = C
To convert a standard form to slope intercept form you first move Ax to the other side of the equation by inverse operations.
2x + 1.50y = 15
-2x -2x
1.50y = -2x + 15
You then divide B (From By) across the whole equation. (If you can't evenly divide make it a fraction)
1.50y = -2x + 15
1.50 1.50
y = -2/1.50x + 10
