Answer:
Step-by-step explanation:
Hi there!
<u>What we need to know:</u>
- Linear equations are typically organized in slope-intercept form:
where m is the slope and b is the y-intercept (the value of y when x is 0) - Parallel lines always have the same slope
<u>1) Determine the slope (m)</u>
In the given equation, 
is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of . Plug this into :
<u>2) Determine the y-intercept (b)</u>
Plug in the given point (-6,-29) and solve for b
Simplify -6 and 2
Add 15 to both sides to isolate b
Therefore, the y-intercept is -14. Plug this back into :
I hope this helps!
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A^2=b^2+c^2-2bc Cos(A)
(270)^2=(255)^2+(442.85)^2-2(255)(442.85)Cos(A)
A=Cos^(-1)(270^2-255^2_(442.85)^2)/(-2*255*442.85)=33.5435
solve for angle A approximately is 33.54 degrees.
sinA/a=SinB/b
Sin33.54/270=SinB/255
B=Sin^(-1)(sin33.54/270*255)approximately is 31.45.
180-31.45-33.54=115.01 is Angle C.
