Answer:
C
Step-by-step explanation:
Consider the vertices of parallelogram JKLM with vertices J(2,2) , K(5,3) , L(5,-3) and M(2,-4).
Perimeter JKLM = Length JK + Length KL + Length LM + Length JM
Length JK = (2,2) (5,3)
The length(or distance) between two points say
and
is given by the distance formula:
![\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D)
Now, length JK = ![\sqrt{(5-2)^{2}+(3-2)^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%285-2%29%5E%7B2%7D%2B%283-2%29%5E%7B2%7D%7D)
=
units
Since, JKLM is a parallelogram. In parallelogram opposite sides are equal in length.
Therefore, LM =
units
Now, length KL = ![\sqrt{(5-5)^{2}+(-3-3)^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%285-5%29%5E%7B2%7D%2B%28-3-3%29%5E%7B2%7D%7D)
= 6 units
Since, JKLM is a parallelogram. In parallelogram opposite sides are equal in length.
Therefore, JM = 6 units
Perimeter of JKLM =
+
+ 6 + 6
= 2
+ 12
= 18.324
Rounding to the nearest tenth, we get
= 18.3 units.
Therefore, the perimeter of JKLM is 18.3 units.
Answer:
The slope is ![-\frac{2}{11}](https://tex.z-dn.net/?f=-%5Cfrac%7B2%7D%7B11%7D)
Step-by-step explanation:
Let
and ![(x_2,y_2)=(11,-3)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29%3D%2811%2C-3%29)
The slope is given by;
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
We plug in the values to get;
![m=\frac{-3-3}{11--22}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-3-3%7D%7B11--22%7D)
Simplify;
![m=\frac{-6}{33}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-6%7D%7B33%7D)
![m=-\frac{2}{11}](https://tex.z-dn.net/?f=m%3D-%5Cfrac%7B2%7D%7B11%7D)