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OlgaM077 [116]
4 years ago
8

What is the value of (Negative 5) Superscript 4?

Mathematics
2 answers:
erica [24]4 years ago
6 0

Answer:

The answer for this question is -15,625

My reasoning is off of the google calculator

                    ∧ ∧

                    Ф  Ф                    

         ∴          ω          ∴

zzz [600]4 years ago
5 0

The value of (Negative 5) Superscript 4 is 625.

Solution:

Given statement is (Negative 5) Superscript 4.

Let us convert statement into expression.

(Negative 5) Superscript 4 = (-5)^4

Value of (-5)^4 = (–5) × (–5) × (–5) × (–5)

Multiply first 2 terms, we get Negative × Negative = Positive

                       = 25 × (–5) × (–5)

Multiply next 2 terms, we get Positive × Negative = Negative  

                       = (–125) × (–5)

Multiply next 2 terms, we get Negative × Negative = Positive  

                       = 625

Value of (-5)^4 = 625

Hence the value of (Negative 5) Superscript 4 is 625.

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What is the value of the expression x÷y when x = 30 and y = 18?
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7 0
3 years ago
Easy math, but not sure what I did wrong.
Ierofanga [76]

Answer:

8

Step-by-step explanation:

In his 5th year, he took 3 times as many exams as the first year.  So the number of exams taken in the 5th year must be a multiple of 3.

If a₁ = 1, then a₅ = 3.  However, this isn't possible because we need 4 integers between them, and a sum of 31.

If a₁ = 2, then a₅ = 6.  Same problem as before.

If a₁ = 3, then a₅ = 9.  This is a possible solution.

If a₁ = 4, then a₅ = 12.  If we assume a₂ = 5, a₃ = 6, and a₄ = 7, then the sum is 34, so this is not a possible solution.

Therefore, Alex took 3 exams in his first year and 9 exams in his fifth year.  So he took 19 exams total in his second, third, and fourth years.

3 < a₂ < a₃ < a₄ < 9

If a₂ = 4, then a₃ = 7 and a₄ = 8.

If a₂ = 5, then a₃ = 6 and a₄ = 8.

If a₂ = 6, then there's no solution.

So Alex must have taken 8 exams in his fourth year.

4 0
3 years ago
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