Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer:
My Plate.
<em>My Plate</em> is the current illustration used to show us how to eat a healthy diet.
- Here is the My Plate diagram.
<em>I hope this helped at all.</em>
Answer:
the answer is seven.
Step-by-step explanation:
Answer:
x+(x+4)=52
Step-by-step explanation:
Let's name the smaller number x.
The greater number would then be (x+4).
<em>The sum of two numbers means we are adding them together.</em>
<u>The equation we could then set up would be:</u>
x+(x+4)=52
<em>Now we can solve the equation to find the two numbers if needed.</em>
<u>Here is how:</u>
x+x+4=52
Combine like terms.
2x+4=52
Subtract 4 from both sides.
2x=48
Divide both sides by 2
x=24
The smaller number is 24.
24+4=28
The larger number is 28.
we know that
diameter of the base of a cylindrical can= 4 in----------> r=2 in
h=6.5 in
[surface area]=2*[pi*r²]+[2*pi*r*h]
then
[surface area]=2*[pi*2²]+[2*pi*2*6.5]=[ 25.13 ]+[ 81.68 ]=106.81 in²
the answer is 106.8 in²
