What is the mean of -14,-10,-1,and -10?

Damm [24]

Answer: Choice D. $6.44 \times 10^{-4}$

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Work Shown:

We multiply the coefficients 9.2 and 7 to get 64.4, which is the same as 6.44*10^1 in scientific notation. When multiplying exponential expressions with the same base, we add the exponents

This is what the steps could look like

$\left(9.2 \times 10^{-9}\right)\times\left(7 \times 10^{4}\right)\\\\\left(9.2\times7\right)\times\left(10^{-9} \times 10^{4}\right)\\\\\left(64.4\right)\times\left(10^{-9+4}\right)\\\\\left(6.44\times 10^{1}\right)\times\left(10^{-5}\right)\\\\6.44\times\left(10^{1}\times 10^{-5}\right)\\\\6.44\times\left(10^{1+(-5)}\right)\\\\6.44\times 10^{-4}\\\\$

The final result is in scientific notation as the coefficient c is restricted such that $0 \le c < 10$

7 0

3 years ago

HELP PLSSS giving out the brainliest answer !!! help asap !!!

GrogVix [38]

Answer:

A 45/28

Step-by-step explanation: because a tangnt means a a straight line or plane that touches a curve or curved surface at a point, but if extended does not cross it at that point. so 45 and 28 are on it so it has to be A

3 0

3 years ago

Whats the order from least to greatest 3/7, 41% ,0.4

nikitadnepr [17]

0.4, 41%, 3/7

Explain: 0.4 is 40%, which is less than 41%. 3/7 is about 43%

3 0

3 years ago

Question 2 of 20 :

Dennis_Churaev [7]

Answer:

A

Step-by-step explanation:

(3a^4-2a^2+5a-10)-(2a^4+4a^2+5a-2)

a^4-6a^2-8

5 0

3 years ago

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.

Ulleksa [173]

Answer:

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

Step-by-step explanation:

We are given the following information in the question:

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.2 minutes.

The distribution function can be written as:

$f(x) = \lambda e^{-\lambda x}\\\text{where lambda is the parameter}\\\\\text{Mean} = \mu = \displaystyle\frac{1}{\lambda}\\\\\Rightarrow 1.2 = \frac{1}{\lambda}\\\\\lambda = 0.84 \\f(x) = 0.84 e^{0.84 x}$

The probability for exponential distribution is given as:

$P( x \leq a) = 1 - e^{\frac{-a}{\mu}}\\\\P(a \leq x \leq b) = e^{\frac{-a}{\mu} -\frac{-b}{\mu}}$

a) P( time between the next two calls will be 54 seconds or less)

$P( x \leq 0.9)\\= 1 - e^{\frac{\frac{-54}{60}}{1.2}} = 0.52763$

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

b) P(time between the next two calls will be greater than 118.5 seconds)

$p( x > \frac{118.5}{60}) = P(x > 1.975)\\\\ = 1 - P(x \leq 1.975) \\\\= 1 -1+ e^{\frac{-1.975}{1.2}}\\\\= 0.19285$

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

6 0

3 years ago