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Vlad [161]
3 years ago
8

What is 28 times 4 over 7 ]

Mathematics
2 answers:
stich3 [128]3 years ago
7 0

Answer:

16

Step-by-step explanation:

28*4/7

28*4=112

112/7=16

ddd [48]3 years ago
3 0

Answer:

16

Step-by-step explanation:

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8(t+ 4) = 24 what is t?​
EastWind [94]

Answer:

pop

Step-by-step explanation:

3 0
3 years ago
A 35 - m tall building casts a shadow. the distance from the top of the building to the tip of the shadow is 36 m . find the len
Nookie1986 [14]
The illustration of the program is shown in the figure. The missing value is the length of the shadow, that is the base of the right triangle. Since the figure is a right triangle, we can use the pythagorean theorems

c^2 = a^2 + b^2

where c is the longest length or the hypotenuse and a and b are the other two shorter legs. Let's denote the length of the shadow as 'a'.

a = √(c^2 - b^2)
a = √(36^2 - 35^2)\
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5 0
4 years ago
Read 2 more answers
Express the rational number as a terminating or repeating decimal number
tresset_1 [31]
A & d are the same, but i think it’s that
5 0
3 years ago
Casey was twice as old as his sister 3 years ago. Now he is 5 years older than his sister. How old is Casey?
Margarita [4]
Let x is Casey's sister age.
<span>3 years ago: 
</span><span>Casey was twice as old as his sister: 2a - 3
Now: 
</span><span>he is 5 years older than his sister: a + 5

2a - 3 = a + 5
subtract a to both sides
2a - 3 -a = a + 5 - a
simplify
a - 3 = 5
add 3 to both sides
a - 3 + 3 = 5 + 3
simplify
a = 8

His sister age is 8 years old now.
</span>Now: 
he is 5 years older than his sister: a + 5 = 8 + 5 = 13
<span>
proof: 
so 3 years ago,
his sister age: 8 - 3 = 5
Casey age 3 years ago:
13 - 3 = 10 (</span>C<span>asey was twice as old as his sister 3 years ago</span>)
<span>
Answer:
Casey is 13 years old now.


</span>
4 0
4 years ago
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A design on the surface of a balloon is 9 cm wide when the balloon holds 62 cm3 of air. How much air does the balloon hold when
Nimfa-mama [501]
\bf \qquad \qquad \textit{ratio relations}&#10;\\\\&#10;\begin{array}{cccllll}&#10;&Sides&Area&Volume\\&#10;&-----&-----&-----\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\implies \cfrac{\sqrt{9}}{\sqrt{18}}=\cfrac{\sqrt[3]{62}}{\sqrt[3]{x}}

\bf \\\\\\&#10;\cfrac{3}{3\sqrt{2}}=\cfrac{\sqrt[3]{62}}{\sqrt[3]{x}}\implies \cfrac{1}{\sqrt{2}}=\cfrac{\sqrt[3]{62}}{\sqrt[3]{x}}\implies \sqrt[3]{x}=\sqrt{2}\cdot \sqrt[3]{62}&#10;\\\\\\&#10;x=\left( \sqrt{2}\cdot \sqrt[3]{62} \right)^3\implies x=\sqrt{2^3}\cdot \sqrt[3]{62^3}\implies x=2\sqrt{2}\cdot 62&#10;\\\\\\&#10;\boxed{x=124\sqrt{2}}
8 0
4 years ago
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