Given:
Right triangle with one angle 45°
To find:
The value of q and r.
Solution:
Opposite to θ = 16
Adjacent to θ = r
Hypotenuse = q
Using trigonometric ratio formula:
The value of tan 45° = 1
Do cross multiplication, we get
r = 16
Using trigonometric ratio formula:
The value of sin 45° = 
.
Do cross multiplication, we get
The value of r is 16 and the value of q is 
.
Answer:
8274
Step-by-step explanation:
Answer:
1. 20.505N
2.8.876N
3. -13.686N
Step-by-step explanation:
1. xcos75 + xsin75 = 26N
x(cos75+sin75) = 26; x = 26/(cos75+sin75)
x = 26/1.2247 = 21.229
vertical component is 21.229 sin75 = 20.505 N
2. xcos30 + xsin30 = 14N
x(cos30 + sin30) = 14; x = 14/1.366 = 10.249
horizontal component is 10.249 x cos30 = 8.876N
3. net force on the vertical direction.
xcos37 + xsin37 = 24
x(cos37+sin37) = 24; x = 24/(cos37+sin37) = 24/1.400 = 17.137
verical component is 17.137 x sin37 =10.314
we are given that the box excert a force of 22N downwards, so the net vertical component is 10.314 - 24 = -13.686N
