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ankoles [38]
3 years ago
14

How do you do you solve this

Mathematics
2 answers:
Ivahew [28]3 years ago
7 0

Answer:

5/7

Step-by-step explanation:

7b^2 - 19b + 10 solve by simplifying the expression.

belka [17]3 years ago
3 0
7b^2 - 19b + 10
(b - 2)(7b - 5)

b1 = 2 ; b2 = 5/7
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SERIOUS MATH HELP PLEAZE<br> SHOW WORK OR AN EXPLANATION<br> HELPPPPPPPPPPPP
Natali5045456 [20]

Answer:

x=3

Step-by-step explanation:

x^2 = 6x - 9

Subtract 6x from each side

x^2 -6x = -9

Add 9 to each side

x^2 -6x+9 = 0

Factor  

what 2 numbers multiply to 9 and add to -6

-3*-3 = 9

-3+-3 =-6

(x-3)(x-3) = 0

Using the zero product property

x-3 =0    x-3=0

x=3 with multiplicity 2

4 0
3 years ago
Question in attachment
kiruha [24]

Answer:

1. a= 7, A = 49 degrees

Side A = 7 , Side B = 24, Side C = 25

A= 49 degrees, C = 90 degrees , B=41

2. A= 4, B = 6.9, C=8

A= 22 degrees, B = 68, C= 90

3. A= 7, B = 14.4, C=16

A= 45 , B=45  , C=90

6 0
3 years ago
A ladder is placed against the side of a house. The top of the ladder is 12 feet above the ground. The base of the ladder is 5 f
Colt1911 [192]
This is the Pythagorean theorem where the 2 legs of a triangle squared add up to equal the squared hypotenuse (a^2 + b^2 = c^2)

The equation would be
12^2 + 5^2 = x^2

144 + 25 = 169

The square root of 169 = 13

Answer - 13 ft
3 0
3 years ago
Let x stand for the number of bananas in one bag. write an equation to find x.
xz_007 [3.2K]
(7-1)/3=x
(14-2)/4=x
1. x=2
2. x=3

If you are looking for the number of bananas per bag you must first subtract your remainders from the total number of bananas, then divide those bananas by the number of bags and you have your answer.
8 0
2 years ago
Read 2 more answers
HEEEEELP!!!!!!!!!!!!!11 I WILL MARK BRAINLIEST kx-3y=4 4x-5y=7 k is constant and x and y are variables, for what value of k will
Studentka2010 [4]

Answer:

<h2>               A.  ¹²/₅</h2>

Step-by-step explanation:

There is no solution for system of equations:  a_1x+b_1y=c_1\\a_2y+b_2y=c_2

if:     a_1=a_2\quad and\quad b_1=b_2\quad and\quad \bold{c_1\ne c_2}

so first, we we need to transform the equations to the form where the coefficients at y will be the same:

kx-3y=4\\ 4x-5y=7\\\\ (kx-3y)\cdot5=4\cdot5\\ (4x-5y)\cdot3=7\cdot3\\\\ 5kx-15y=20\\ 12x-15y=21

Now we have  b₁=b₂ and c₁≠c₂ so the system has no solution if a₁=a₂

5k = 12

÷5     ÷5

k = ¹²/₅

7 0
3 years ago
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