All categories

4 years ago

The square of the binomial x-4 has the form x^2 - ax + 16. What is the value of a?

Mathematics

1 answer:

Fantom [35]4 years ago

5 0

A would be 8.
(x-4)(x-4)=
x^2-8x+16

You might be interested in

HELP I NEED HELP ASAP

victus00 [196]

Answer:

Step-by-step explanation:

3 0

3 years ago

Find the value of x.<br> 101 x +29

iVinArrow [24]

Answer:

x = 50

Step-by-step explanation:

101 + (x + 29) = 180

130 + x = 180

x = 180 - 130

x = 50

4 0

3 years ago

Read 2 more answers

Turk varmi arkaadadlaaar

Artist 52 [7]

What do you want us to answer?

4 0

3 years ago

Kiran and Mai are trying to figure out if this equation is an identity, what do you think

ValentinkaMS [17]

Expanding the left side of the equation, it is found that since <u>both sides are equal</u>, yes, it is an identity.

An equality represents an identity if <u>both sides are equal</u>.

In this problem:

$(a - b)^4 = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4$

Expanding the left side:

$(a - b)^2(a - b)^2 = a^4 - 4a^3b + 6a^2b^2 + 4ab^3 + b^4$

$(a^2 - 2ab + b^2)(a^2 - 2ab + b^2) = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4$

$a^4 - 4a^3b + + 6a^2b^2 - 4ab^3 + b^4 = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4$

Since <u>both sides are equal</u>, yes, it is an identity.

A similar problem is given at brainly.com/question/24866308

7 0

2 years ago

There are 46 children going to a party. 18 will wear black costumes, 12 will wear orange costumes and some will wear both black

Juliette [100K]

The number of children who wore both orange and black will be 8.

<h3>What is Algebra?</h3>

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

PEMDAS rule means for the Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to solve the equation in a proper and correct manner.

There are 46 children going to a party. 18 will wear black costumes, 12 will wear orange costumes and some will wear both black and orange.

Then the number of children who wear costumes and black & orange. Then we have

⇒ 46 - 18 - 12

⇒ 46 - 30

⇒ 16

Half of the guests will go in costumes that are neither black nor orange. Then we have

⇒ 16 / 2

⇒ 8

Then the number of the children who orange and black will be

⇒ 16 - 8

⇒ 8

The number of children who wore both orange and black will be 8.

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ2

3 0

2 years ago