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Alika [10]
2 years ago
15

Kiran and Mai are trying to figure out if this equation is an identity, what do you think

Mathematics
1 answer:
ValentinkaMS [17]2 years ago
7 0

Expanding the left side of the equation, it is found that since <u>both sides are equal</u>, yes, it is an identity.

An equality represents an identity if <u>both sides are equal</u>.

In this problem:

(a - b)^4 = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4

Expanding the left side:

(a - b)^2(a - b)^2 = a^4 - 4a^3b + 6a^2b^2 + 4ab^3 + b^4

(a^2 - 2ab + b^2)(a^2 - 2ab + b^2) = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4

a^4 - 4a^3b + + 6a^2b^2 - 4ab^3 + b^4 = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4

Since <u>both sides are equal</u>, yes, it is an identity.

A similar problem is given at brainly.com/question/24866308

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What is the solution to the system of equations below?
AnnyKZ [126]

Answer:

x=9, y=3

Step-by-step explanation:

-4x+6y=-18

y=-2x+21

-4x+6(-2x+21)=-18

-4x-12x+126=-18

144=16x

x=9

y=-2x+21

y=-18+21

y=3

8 0
3 years ago
The side length of a square ice cube is claimed to be 1.0 inches, correct to within 0.001 inch. Use linear approximation to esti
Olenka [21]

Answer:

0.012

Step-by-step explanation:

Linear approximation says that,

f(x) \approx f(x_o)+f'(x_o)(x-x_o)

For a cube the surface area is 6x^2.

So the side is 1.0 inch in, the surface area is =6\times1^2 = 6 square inches.  

In Linear approximation means you ignore the term x_o^2 , if x_o is a small number, because then x_o^2 will be a very smalle number and that does not contribute much to the error.  

So the surface area is approximately,

6x^2=6x_o^2+12x_o(x-x_o)

So here, x=1.001, x_o=0.001

The error in the area is approximately,

12 \times 0.001=0.012

So the error is 0.012.


3 0
3 years ago
Assume the competing hypotheses take the following form: H0: µ1 – µ2 = 0, HA: µ1 – µ2 ≠ 0, where µ1 is the population mean for p
DedPeter [7]

Answer:

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

Step-by-step explanation:

H0: µ1 – µ2 = 0

HA: µ1 – µ2 ≠ 0

We have given,

The population variances are not known and cannot be assumed equal.

The test statistic for the test is

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

Where,

\bar x_1 = sample meaan of population 1

\bar x_2 = sample mean of population 2

n_1 = sample size of population 1

n_2 = sample size of population 2

Therefore, this is the test

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

7 0
3 years ago
Please help me with this math problem
givi [52]

It should be c really hope this helps and im right have a blessed day:)

5 0
3 years ago
Is 12.56 greater than or less than 125.6
leva [86]
12.56 is less than 125.6 which could also be written as 12.56<125.6. 12.56 comes farther left on the number line and is of lesser value when compared to the number 125.6.
5 0
3 years ago
Read 2 more answers
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