(2x-y = -3 × y = 0 × (0, 0) × ( -1, 1) × (1, -1) =
(2x - y = -3 × y =0 × (0)) ×, × 0 ×, × 1 ×, × -1
We are given with two functions: f(x) = x + 8 and g(x) = x2 - 6x - 7. In this problem, the value of f(g(2)) is asked. We first substitute g(x) to f(x) resulting to f(x2 - 6x - 7) = x2 - 6x - 7 + 8 = x2 - 6x + 1. If x is equal to 2, then <span>f(g(2)) = 2^</span>2 - 6*2 + 1 equal to -7.
Answer:
16 bicycles and 21 tricycles
Step-by-step explanation:
Both bicycles and tricycles have 1 set of handlebars. Bicycles have 2 wheels while tricycles have 3.
Using this information, set up a system of equations, where b is the number of bicycles and t is the number of tricycles:
b + t = 37
2b + 3t = 95
Solve by elimination by multiplying the top equation by -2:
-2b - 2t = -74
2b + 3t = 95
t = 21
Then, plug in 21 as t into one of the equations:
b + t = 37
b + 21 = 37
b = 16
So, there are 16 bicycles and 21 tricycles
Answer:
1. 54 and 9/20 km
2. 80 mm
3. 1.142 mi
4.0.83333 cm
Step-by-step explanation:
Do them all by the butterfly method.
