One method is called the ac method:-
For example factor
3x^2 + 2x - 21
ac ( first coefficient times the last) = 3*21 = -63
now we need to find 2 factors of -63 which add up to the coefficient of x ( + 2):-
+9 and - 7 look good so we can write the original expression as:-
3x^2 + 9x - 7x - 21
Factor by grouping:-
= 3x(x +3) - 7(x + 3) ( x + 3) is common so:-
= (3x - 7)(x + 3) Answer
Answer: =D
Step-by-step explanation:

- Given - <u>a </u><u>bus </u><u>takes </u><u>6</u><u> </u><u>hours</u><u> </u><u>to </u><u>travel </u><u>a </u><u>particular</u><u> </u><u>distance </u><u>with </u><u>a </u><u>constant</u><u> </u><u>speed </u><u>of </u><u>3</u><u>6</u><u> </u><u>km/</u><u>hr</u>
- To calculate - <u>the </u><u>total </u><u>distance </u><u>travel </u><u>by </u><u>the </u><u>bus</u>
We know that ,

<u>this </u><u>formula</u><u> </u><u>can </u><u>be </u><u>transformed</u><u> to</u><u> </u><u>find</u><u> </u><u>out </u><u>distance</u><u> </u><u>,</u><u> </u><u>as </u><u>follows </u><u>~</u>

now ,
<u>substituting</u><u> </u><u>the </u><u>values </u><u>in </u><u>the </u><u>formula </u><u>state</u><u>d</u><u> </u><u>above </u><u>,</u>

thus ,
<u>the </u><u>bus </u><u>travels </u><u>a </u><u>distance</u><u> </u><u>of </u><u>2</u><u>1</u><u>6</u><u> </u><u>km</u><u> </u><u>in </u><u>6</u><u> </u><u>hours</u>
hope helpful ~
Answer:
6
x
8
Step-by-step explanation:
We'll represent the number with the expression 4x + 7
Then, we'll set up the inequality:
31
4x + 7
55
24
4x
48
6
x
8
Answer:
15x-9x=6x
please mark me as brainliest