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LenKa [72]
2 years ago
9

Determine if the following lines are parallel, perpendicular and neither.

Mathematics
1 answer:
Ivenika [448]2 years ago
7 0

Answer:

parallel lines

Step-by-step explanation:

If two lines are parallel it means that they never intersect

the only way for this to happen is when the slopes are identical (and the y intercepts are different)

This is the case

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17. Let A denote the event that the next request for assistance from a statistical software consultant relates to the SPSS packa
ankoles [38]

Answer:

a. The probability is not equal to 1

b. P (A') = 0.70

c. P ( A U B ) = 0.80

d. P ( A' ∩ B' ) = 0.20

Step-by-step explanation:

a. Because these A and B are disjoint

b. since the probability of  A is 0.30 then the probability of A compliment is

    P(A compliment ) = 1 - P (A)

    P(A compliment ) = 1-0.30

    P(A compliment ) = 0.70

c. Since event are disjoint then intersection of A and B is 0, so probability of A U B is;

       P ( A U B ) = P (A) + P(B) - P(A∩ B)

       P ( A U B ) = 0.30 + 0.50 - 0

       P ( A U B ) = 0.80

d. The inetrsection of compilments of A and B are:

by using De Morgan's Law we have,

                     P ( A' ∩ B' ) = P [(A U B )']

                     P ( A' ∩ B' ) = 1 - P ( A U B )

                     P ( A' ∩ B' ) = 1 - 0.80

                     P ( A' ∩ B' ) = 0.20

5 0
2 years ago
If n is an integer, which conjecture is not true about 2n– 1? A. 2n– 1 is odd if n is positive. B. 2n– 1 is always even. C. 2n–
VladimirAG [237]
B.



Let's simply look at each conjecture and determine if it's true or false.



A. 2n– 1 is odd if n is positive: Since n is an integer, 2n will always be even. And an even number minus 1 is always odd. Doesn't matter if n is positive or not. So this conjecture is true.



B. 2n– 1 is always even: Once again, 2n will always be even. So 2n-1 will always be odd. This conjecture is false.



C. 2n– 1 is odd if n is even: 2n is always even, so 2n-1 will always be odd, regardless of what n is. So this conjecture is true.



D. 2n– 1 is always odd: 2n will always be even. So 2n-1 will always be odd. Once again, this conjecture is true.



Of the 4 conjectures above, only conjecture B is false. So the answer is B.
6 0
3 years ago
Write the polynomial in standard form. Identify the degree and leading coefficient of the polynomial. Then classify the polynomi
Musya8 [376]

Answer:

Standard form: 2c^4 + 6c^2 - c

Degree: 4th

Leading coefficient: 2

Classification: Trinomial

Step-by-step explanation:

In standard form, you have to put the term with the highest exponent first.

With finding the degree, you just look at the highest exponent and that's the degree. 4 is the highest exponent, so it is to the 4th degree.

The leading coefficient is the number attached to the highest exponent. 4 is the highest and the number attached to it is 2.

Classification goes by how many terms there are. Since there are 3, it's trinomial. Tri as in three.

3 0
3 years ago
I need helppppppp plzzzzzz
Zanzabum
14 x 10^3 = 14,000 (the elephants weight)

So the cat weighs 14 pounds
3 0
3 years ago
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You wish to borrow $8000 for debt consolidation. The bank's interest rate for a personal loan is 7.2%. What is your monthly paym
Lisa [10]
<h3>The monthly payment  is $242.44 for loan to paid off in 3 years.</h3>

Step-by-step explanation:

The amount borrowed = Principal = $8000

The rate of interest = 7.2%

Time (T)  = 3 years

Now, Simple Interest = \frac{P\times R \times T}{100}

\implies SI  = \frac{8000 \times 7.2  \times 3}{100}  = 1,728

So, the total interest = $1728

Now, <u>Amount to be paid  = Principal + Interest</u>

⇒ A = $8000 + $1728  = $8728

Also, 1 year = 12 months

⇒  3 years  = 3 x 12 months  = 36 months

So, total amount to be paid in 36 months is $8728.

⇒The  amount to be paid in 1 month is (\frac{8728}{36} )  = 242.44

Hence, the monthly payment  is $242.44 if loan is to paid off in 3 years.

3 0
3 years ago
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