It is d Ik Bc Ik don’t ask why just know it’s d
Step-by-step explanation:
EF = 6x - 4
and it is also the combination of EG and GF.
so,
6x - 4 = EG + GF = EG + 13
6x = EG + 17
now, we have additional information. EF bisects CD. that means it cuts CD in half.
and that means both banks must be off equal size.
5x - 1 = 7x -13
12 = 2x
x = 6
so, back to the first problem
6×6 = EG + 17
36 = EG + 17
19 = EG
No he's not correct
<span>(3 – 6y2)(y2 + 2)
= 3(y2) -6(y2)(y2) - 6y2(2) </span>+ 3(2)<span>
= 3y2 -6y4 - 12y2 </span>+ 6 <span>
= -6y4 - 9y2 +6</span>