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jenyasd209 [6]
3 years ago
8

Complete the paragraph proof. We are given that Ray E B bisects ∠AEC. From the diagram, ∠CED is a right angle, which measures de

grees. Since the measure of a straight angle is 180°, the measure of angle must also be 90° by the . A bisector cuts the angle measure in half. m∠AEB is 45°.

Mathematics
2 answers:
Vilka [71]3 years ago
7 0

Answer: 1. 90, 2. AEC, 3. angle addition postulate

Step-by-step explanation:

Oduvanchick [21]3 years ago
4 0

Answer:

1. 90

2. AEC

3. angle addition postulate

:)

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The length of a rectangle is five less than its width. The area of the rectangle is 84 square feet. Write a quadratic equation i
salantis [7]

<u>Given</u>:

The length of a rectangle is 5 less than its width.

The area of the rectangle is 84 square feet.

We need to determine the quadratic equation in standard form that represents the area of the rectangle.

<u>Dimensions of the rectangle:</u>

Let l denote the length of the rectangle.

Let w denote the width of the rectangle.

Since, it is given that the length is 5 less than its width, it can be written as,

l=5-w and w=w

<u>Area of the rectangle:</u>

The area of the rectangle can be determined using the formula,

A=length \times width

Substituting A = 84, l=5-w and w=w, we get

84=(5-w)\times w

84=5w-w^2

Adding both sides of the equation by w², we have;

w^2+84=5w

Subtracting by 5w on both sides, we get;

w^2-5w+84=0

Thus, the quadratic equation in standard form for the area of the rectangle is w^2-5w+84=0

4 0
3 years ago
Help me please!?!?!?!
eduard
The answer would be A
6 0
3 years ago
The null hypothesis for an ANOVA is that all treatments/samples come from populations with the same mean. The alternative hypoth
LenKa [72]

Answer:

Alternative hypothesis: "AT LEAST ONE" of the population means is different from the others

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have n groups and we want to check if the population means are equal, th best way to check this it's with an ANOVA test.

The hypothesis for this case are:

Null hypothesis: \mu_{1}=\mu_{2}=\dots =\mu_{n}

Or in words:

Null hypothesis: All treatments/samples come from populations with the same mean

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=1.2,\dots ,n

Or we can say:

Alternative hypothesis: "AT LEAST ONE" of the population means is different from the others

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(10y - 4) + (7y + 8) + (7y - 5) + (4y - 5) =

= 10y - 4 + 7y + 8 + 7y - 5 + 4y - 5 =

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Answer:

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