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Masteriza [31]
3 years ago
7

Which list correctly shows how to find the greatest common factor among three numbers?

Mathematics
1 answer:
valina [46]3 years ago
5 0
I don’t see any lists.
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F(x) = x^2. What is g(x)?
Murrr4er [49]
C would be your answer i hope i helped you :) sorry if i’m incorrect. i’m not sure
6 0
2 years ago
Please helppp!!! Latrece sells bracelets for a fixed price at the craft show for every bracelet she sells she gives her business
anyanavicka [17]

Answer:

Step-by-step explanation:

Answer:

$7.50

Step-by-step explanation:

$207 / 18 = $11.50

Each bracelet costs $11.50.

$11.50 - $4 = $7.50

She receives $7.50 for every bracelet she sells.

8 0
3 years ago
You have 32 foot long fence there are 4 equal sections you paint 1/3 of on section what fraction of the fence did you paint
zheka24 [161]
2/32. Divide 32 by 4 to equal 8, and then divide 8 by 3 because that’s how much you painted, a third of a fourth
8 0
3 years ago
For the graphed exponential equation, calculate the average rate of change from x = −3 to x = 0.
iragen [17]

Answer:

-\frac{7}{3}

Step-by-step explanation:

To solve this, we are using the average rate of change formula:

m=\frac{f(b)-f(a)}{b-a}

where

m is the average rate of change

a is the first point

b is the second point

f(a) is the function evaluated at the first point

f(b) is the function evaluated at the second point

We want to know the average rate of change of the function f(x)=0.5^x-6 form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words, a=-3 and b=0.

Replacing values

m=\frac{f(b)-f(a)}{b-a}

m=\frac{0.5^0-6-(0.5^{-3}-6)}{0-(-3)}

m=\frac{1-6-(8-6)}{3}

m=\frac{-5-(2)}{3}

m=\frac{-5-2}{3}

m=\frac{-7}{3}

m=-\frac{7}{3}

We can conclude that the average rate of change of the exponential equation form x = -3 to x = 0 is -\frac{7}{3}

4 0
3 years ago
Find the exact value of the composition. arccos (cos pi/2)
Genrish500 [490]
<span>arccos (cos pi/2)=?
</span>cos pi/2=0, arccos (0)=?, we know that cos pi/2=0, so cos^-1 (o)= Pi/2, but cos^-1 (o)=arccos (0), so arccos (cos pi/2)=Pi/2
6 0
3 years ago
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