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3 years ago

2

Mathematics

1 answer:

goblinko [34]3 years ago

3 0

Answer: 60.5% loss

Step-by-step explanation:

Loss = Cost Price – Selling Price =$1900-$750= $1150

% loss= Total loss/Cost price ×100

=1150/1900×100

=60.5%

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Which expression is equivalent to 3m + 1 - m? 2 + m - 1 + - m 1 + m 3m - 1 3m

Rasek [7]

Answer:

I believe it would be A) 2 + m - 1 + - m

5 0

3 years ago

Anybody help me to solve this question.

Mumz [18]

Answer:

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are\ in\ AP$

Step-by-step explanation:

Given that $(b-c)^2, (c-a)^2 , (a-b)^2$ are in AP

To prove: $\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}$ are in AP

From given as we know if p , q, r are in AP then 2q= p+r.

$2(c-a)^2= (b-c)^2+(a-b)^2\\\\\Rightarrow 2(c^2+a^2-2ac)=b^2+c^2-2bc+a^2+b^2-2ab\\\\\Rightarrow 2c^2+2a^2-4ac= 2b^2+c^2+a^2 -2bc-2ab\\\\\Rightarrow a^2+c^2-2b^2-4ac= -2bc-2ab\\\\\Rightarrow a^2-2b^2+c^2= 4ac-2bc-2ab$

Now

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}2\dfrac{1}{(c-a)} =\dfrac{1}{(b-c)}+\dfrac{1}{(a-b)}\\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-b+b-c}{(b-c)(a-b)} \\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-c}{(b-c)(a-b)} \\\\\Rightarrow2(b-c)(a-b) = (c-a)(a-c) \\\\\Rightarrow 2(ab-b^2-ac+bc)= -(a-c)^2\\\\\Rightarrow 2ab- 2b^2-2ac+2bc = -a^2-c^2+2ac\\\\\Rightarrow a^2-2b^2+c^2=4ac-2ab-2bc$

Which is the result of AP

Hence proved

6 0

3 years ago

Can you kindly help me out please?!

Mila [183]

Answer:

32h^7

Step-by-step explanation:

(4h^4)3=64h^12

64h^12/2h^5=

32h^12/2h^5=32h^7

Hope this helps :)

5 0

3 years ago

Please help!!!

Nonamiya [84]

Answer:

c. $2a^3x^4-3a^3x^3+a^4x^2$

d. $63x^5y^3-30x^2y^4-7x^3y^2$

Step-by-step explanation:

For this exercise you need to remember the following:

1. The multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-$

2. The Product of powers property, which states that:

$(a^m)(a^n)=a^{(m+n)}$

3. The Distributive property:

$a(b\±c)=ab\±ac$

Knowing that, you can solve the multiplication of the polynomials:

c. $(-2ax^2+3ax-a^2)(-a^2x^2)=\\\\=(-2ax^2)(-a^2x^2)+(3ax)(-a^2x^2)+(-a^2)(-a^2x^2)=2a^3x^4-3a^3x^3+a^4x^2$

d. $(6.3x^3y-3y^2-0.7x)(10x^2y^2)=\\\\=(6.3x^3y)(10x^2y^2)+(-3y^2)(10x^2y^2)+(-0.7x)(10x^2y^2)=63x^5y^3-30x^2y^4-7x^3y^2$

8 0

3 years ago

0.25 is inches distance 5.5 is distance what is process

PIT_PIT [208]

Unfortunately, your problem statement appears to be incomplete. What distance are you talking about? Have you an illustration to share? How does 0.25 inches fit into this problem? Please try again. Double-check to ensure that you have shared all of the problem you wish to solve.

8 0

3 years ago