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leva [86]
3 years ago
15

Find the mean absolute deviation of the data below l. Fill in the table. Round your answer to the nearest tenth. Show work for f

ull credit.

Mathematics
1 answer:
Evgen [1.6K]3 years ago
3 0

To find the mean absolute deviation of the data, start by finding the mean of the data set. Find the sum of the data values, and divide the sum by the number of data values. Find the absolute value of the difference between each data value and the mean: |data value – mean

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2 of the dozen eggs in a cartoon are cracked about what percent of the carton is not cracked
pychu [463]

well, a carton has a dozen, namely 12 or the 100%, two were cracked.

if we know 12 is the 100%, what is 2 off of it in percentage?


\bf \begin{array}{ccll}
amount&\%\\
\cline{1-2}
12&100\\
2&x
\end{array}\implies \cfrac{12}{2}=\cfrac{100}{x}\implies x=\cfrac{2\cdot 100}{12}\implies x=16.\overline{66}

4 0
3 years ago
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PLEASE THINS IS DUE BY 1 P.M TODAY. PLEASE HELP ME
zaharov [31]

6 {x}^{2}  {y}^{2} (y + 3xy + 6x)
6 0
3 years ago
Choose the function that represents the data in the table.
viva [34]

y = 2 {x}^{2}  - 3

\huge\underline\mathtt\colorbox{cyan}{Explanation thing:}

Using hit and trial, you van find it pretty easily-

  • Putting x=0, we get y=-3
  • Putting x=1, we get y=-1
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You can try it for yourself as well, for me, I couldn't find any other option appropriate.

4 0
2 years ago
20 points -simplify fully
natulia [17]

Answer:

4√7

Step-by-step explanation:

5√7 +   √7 -  2√7

Taking out common term, √7.

= √7 ( 5 + 1 - 2)

Simplify the terms in the bracket.

= √7 (4)

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7 0
3 years ago
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A pizza parlor offers pizzas with diameters of 8 in, 10 in, and 12 in. find the area of each size pizza. round to the nearest te
MaRussiya [10]
Area od pizza, A = Pi*Diameter^2/4

A1 = Pi*8^2/4 = 50.27 in^2
A2 = Pi*10^2/4 = 78.54 in^2
A3 = Pi*12^2/4 = 113.10 in^2

Cost (C) per sq. in;
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C2 = 78.54/12 = $6.55
C3 = 113.10/18 = $6.28

The best buy is the first pizza with 8 in diameter as it costs the least per sq. inch.
3 0
3 years ago
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