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Makovka662 [10]
3 years ago
10

Is 400 pints greater than less than or equal to 100 gallons

Mathematics
1 answer:
adell [148]3 years ago
6 0
400 Imperial pints are less than 100 Imperial gallons, 
400 pints = 50 gallons.
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Solve the exponential equation: 4x - 2 = 2x​
svetlana [45]

Answer:

x= 1

Step-by-step explanation:

Solve

Let's solve your equation step-by-step.

4x−2=2x

Step 1: Subtract 2x from both sides.

4x−2−2x=2x−2x

2x−2=0

Step 2: Add 2 to both sides.

2x−2+2=0+2

2x=2

Step 3: Divide both sides by 2.

2x

2

=

2

2

x=1

8 0
2 years ago
PLEASE HELP! WILL MARK BRAINLIEST!
____ [38]

Answer:

b. 75

Step-by-step explanation:

a(n) = a1 + d(n-1)

a(n) = 8.5 + 3.5(n - 1)

a(20) =  8.5 + 3.5(20 - 1)

a(20) =  8.5 + 3.5(19)

a(20) = 8.5  + 66.5

a(20) = 75

4 0
3 years ago
Read 2 more answers
1 4/5 lbs into ounces
AURORKA [14]
1 4/5lbs is equal to 28.8oz
7 0
2 years ago
Read 2 more answers
Can someone help me with this
ludmilkaskok [199]

Answer:

A

Step-by-step explanation:

1/2r +1/2= -2/7r  -29/7 Subtracting 1/2 from both sides

1/2r +1/2 - 1/2= -2/7r  -29/7- 1/2

1/2r = -2/7r  - 29(2)-7/14

1/2r = -2/7r  -65/14

3 0
2 years ago
Report Error Suppose $P(x)$ is a polynomial of smallest possible degree such that: $\bullet$ $P(x)$ has rational coefficients $\
motikmotik

Answer:

We want a polynomial of smallest degree with rational coefficients with zeros in \sqrt{7}, 1 - \sqrt{6} and -3. The last root gives us the factor (x+3). Hence, our polynomial is

P(x) =(x+3)q(x)

where q is a polynomial with rational coefficients and roots \sqrt{7} and 1 - \sqrt{6}. The root \sqrt{7} gives us a factor x-\sqrt{7}, but in order to obtain rational coefficients we must consider the factor x^2-7.

An analogue idea works with 1 - \sqrt{6}. For convenience write  x - 1 + \sqrt{6} = ( x - 1) + \sqrt{6}. This gives the factor (x-1)^2-6. Hence,

P(x) = (x+3)(x^2-7)((x-1)^2-6)=x^5+x^4-18x^3-22x^2+77x+105

Notice that P(-1)=24. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

P(x) =(1/3)x^5+(1/3)x^4-6x^3-(22/3)x^2+(77/3)x+35

Step-by-step explanation:

We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type x-\sqrt7 will introduce in the expression, we need to multiply by its conjugate x+\sqrt7. Hence, we will obtain x^2-7 that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.

4 0
2 years ago
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