Please help with Algebra!!! 10 points!

ELEMENTARY SCHOOL MATHEMATICS 13 points Previous question Next question Use Compatible Numbers To Estimate The Quotient.(The Sla

Ahat [919]

1. 5514 divided by 82 you have to find out how many times 82 goes into 551 (because it won't go into 5 or 55 now 82 goes into 551 6 times and you multiply 82 and 6 to get 492 (which is the closest you can get to 551 without going over) now you subtract 551-492 to get 59 now you carry down your 4 and add it to the end of the equation and your number changes into 594 now 82 times 7 is 574 when you subtract you get 20 now you add a decimal point and you carry down the 0 to make your number 200 now you do 82 times 2 to get 164 when you subtract you get 36 now you carry down the 0 and get 360 so you multiply 82 by 4 to get 328 so your answer is 67.24.Hope this helps. I can add a picture if you need one.

8 0

2 years ago

4. The trajectory of a model rocket can be modelled by the equation h = - 3t^2 + 24t- 25, where h is the height of the rocket in

Alex Ar [27]

Answer:

It's too short. Write at least 20 characters to explain it well.

5 0

3 years ago

What's 10x(2+3) divide by 5

Katarina [22]

10

2+3=5 10x5=50 50 divided by 5= 10
Hope this helps!

8 0

2 years ago

Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9

nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = $\left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]$ = 1(1-4) - 2(2-6) + 3(4 - 3)

= 1(-3) - 2(-4) + 3(1)

= -3+8+3 = 8

also D $\neq 0$

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx = $\left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]$ = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = $\frac{Dx}{D}$ = $\frac{16}{8}$ = 2

similarly

Dy = $\left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right]$ = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = $\frac{Dy}{D}$ = 0

Dz= $\left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right]$ = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = $\frac{Dz}{D}$ = $\frac{24}{8} = 3$

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0

2 years ago

True or false: for any function, x=f^-1(y), then y=f(x)

kozerog [31]

YES

We can work out the inverse using Algebra. Put "y" for "f(x)" and solve for x:

The function: f(x)=2x+3
Put "y" for "f(x)": y=2x+3
Subtract 3 from both sides:
y-3=2x
Divide both sides by 2:
(y-3)/2=x
Swap sides: x=(y-3)/2
Solution (put "f-1(y)" for "x") : f-1(y)=(y-3)/2

6 0

2 years ago

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