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Vera_Pavlovna [14]
3 years ago
13

ALL OF A SUDDEN EVERYONE IS CLUELESS IN GEOMATRY?!?! COME ON!!! I LITERALLY HAVE 12 MINUTES LEFT! HELP ME PLEASE! I AM STRESSED

Mathematics
1 answer:
Nataly [62]3 years ago
5 0
The answers are a d f
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Read 2 more answers
Determine whether the relation is a function: {(6, 1), (8, –3), (6, 7)}.
ICE Princess25 [194]

Hello there! The answer would be the first one, or No. At least one output results in two inputs.

When dealing with functions: you must remember that x does not repeat. So, lets look at the relation given, {(6, 1), (8, –3), (6, 7)}. You can see that x does repeat, so this is not a function. This eliminates second and fourth option choices. Out of the options A and C, A would be your choice since x is the input value and y is the output value, and there are two input values.

Hope his helps and have a  great day!

5 0
3 years ago
HELP When 2((Three-fifths x + 2 and three-fourths y minus one-fourth x minus 1 and one-half y + 3)) is simplified, what is the r
lesya692 [45]

Answer:

<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>

Step-by-step explanation:

Given the expression 2(\frac{3x}{5}+2\frac{3y}{4}-\frac{x}{4}-1 \frac{1}{2}y+3)

To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

= 2(\frac{3x}{5}-\frac{x}{4}-1 \frac{1}{2}y+2\frac{3}{4}y+3)\\= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\

Then we find the LCM of the resulting function

= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\= 2(\frac{12x-5x}{20} - (\frac{6y-11y}{4})+3)\\= 2(\frac{7x}{20}- (\frac{-5y}{4})+3 )\\= 2(\frac{7x}{20}+ \frac{5y}{4}+3 )\\= \frac{7x}{10} + \frac{5y}{2} +6\\=  \frac{7x}{10} + 2\frac{1}{2}y+6\\

The final expression gives the required answer

7 0
3 years ago
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