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kondaur [170]
3 years ago
5

At the end of the summer, a store marks down all the outdoor furniture 20%. A family bought 4 chairs that originally cost $102.

How much was the cost of the 4 chairs?
Mathematics
1 answer:
crimeas [40]3 years ago
5 0

Answer:

$81.60

Step-by-step explanation:

A 20% markdown means that the chairs were sold at 80% of the original cost.

Original cost = $102

markdown = 20%

Cost after markdown = original cost* (1-markdown)

Cost after markdown = 102 *(1 - 0.20)

= 102*0.80

= 81.6

Therefore, the 4 chairs were sold at a total cost of $81.60

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Find the value of this expression if x = 2 and<br> y= 1.
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Answer: 2/5

Step-by-step explanation:

xy^2

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5

If x = 2 and y = 1

x * y^2 2 × 1^2

----------- -----------

5 5

2

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5

6 0
3 years ago
What else would need to be congruent to show that ABC=DEF by SAS?
KonstantinChe [14]

Answer:

A

Step-by-step explanation:

SAS = side-angle-side

This means that, in order to prove that the triangles are congruent, they must have two congruent sides with the angle between them to the same.

We know that sides AB, ED, AC, and DF are all congruent as they all have a single mark through them. From this, you can conclude that the triangles already share two sides. All we need now is the angles in between to be congruent. This means that angle A and angle D need to be congruent.

I hope this helps!

7 0
3 years ago
Chip begins his ride slowly but then stops to talk with some friends. After a few minutes, he continues his ride, gradually incr
lapo4ka [179]
What is the question? I don't understand please explain?
6 0
3 years ago
For the real-valued functions f(x)=2x+1 and g(x)=sqrt(x-1), find the composition f o g and specify its domain using interval not
Anettt [7]

Answer:

fog = 2√(x-1) + 1

Domain = [1, \infty)

Step-by-step explanation:

Given the functions  f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog

fog = f(g(x))

f(g(x)) = f(√(x-1))

f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)

f(√(x-1)) = 2(√(x-1))+1

f(√(x+1)) = 2√(x-1) + 1

fog = 2√(x-1) + 1

<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>

If x-1≥0

x≥0+1

x≥1

This means the range of variable x must be values of x greater than or equal to 1.

Domain = [1, \infty)

8 0
3 years ago
|2x| ≤ x + 3
r-ruslan [8.4K]

Answer:

[-1,3]

Step-by-step explanation:

|2x|<x+3

calculate the absolute value

2*|x|<x+3

move < to left

2*|x|-x<3

split into possible cases

2x-x<3, x<0

2*(-x)-x<3, x<0

solve inequalities

[0,3]

[-1,0]

find union

[-1,3]

3 0
3 years ago
Read 2 more answers
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