Please help!! Is this statement always,sometimes,or never true

Mathematics

2 answers:

andriy [413]3 years ago

7 0

It's always true you can test yourself by choosing random numbers

Kipish [7]3 years ago

4 0

Always because the higher the negative he less its and the same for he positive side

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A tree struck by lightning broke at a point 12 ft above the ground as shown. What was the height of the tree to the nearest tent

forsale [732]

51, because 39+12=51. You just add both parts of the tree. Please Rate Brainliest.

6 0

3 years ago

Two sides of a triangle measure 9 centimeters and 37 centimeters what could the length of the third triangle?

STALIN [3.7K]

Step-by-step explanation:

One side of a triangle is 9 cm and other side is 37 cm. We need to find what could be the length of the third side of the triangle.

If we add one and other side i.e. 9 cm + 37 cm = 46 cm

If we subtract one and other side i.e. 37 cm - 9 cm = 28 cm

We know that, the length of the third side must be less than the sum of the other two sides and greater than the difference between the other two sides.

Thus, the third side could be between 46 cm and 28 cm.

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3 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm