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shtirl [24]
3 years ago
9

Factor completely 2x^3y^4-8x^2y^3+6xy^2

Mathematics
1 answer:
Maru [420]3 years ago
6 0

Answer:

2 x y^2 (x y - 1) (x y - 3)

Step-by-step explanation:

2x^3y^4-8x^2y^3+6xy^2

each term contains 2xy^2 so factor that out

2xy^2(x^2y^2 -4xy+3)

then lets factor the inside

what terms multiply together to give us +3 and add to -4

-3* -1 = 3     -3+-1 =-4

2 x y^2 (x y - 1) (x y - 3)

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QveST [7]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The correct answer choice would be B) 15 · 3 if the three is written as an exponent. If the 3 isn't an exponent, none of the choices will work.

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~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

6 0
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Read 2 more answers
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Check by substitution to determine whether $15 and $10 are correct.  If not, please show your work, so that someone else or I could step back in and help.

</span>
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