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shtirl [24]
3 years ago
9

Factor completely 2x^3y^4-8x^2y^3+6xy^2

Mathematics
1 answer:
Maru [420]3 years ago
6 0

Answer:

2 x y^2 (x y - 1) (x y - 3)

Step-by-step explanation:

2x^3y^4-8x^2y^3+6xy^2

each term contains 2xy^2 so factor that out

2xy^2(x^2y^2 -4xy+3)

then lets factor the inside

what terms multiply together to give us +3 and add to -4

-3* -1 = 3     -3+-1 =-4

2 x y^2 (x y - 1) (x y - 3)

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Katt and sanjeev are collecting money for charity. For every £2 that kat collects, sanjeev collects £3. They collect £255 in tot
il63 [147K]

Answer: Kate = £102

Sanjeev = £153

Step-by-step explanation:

From the question, we are informed that for every £2 that kat collects, sanjeev collects £3. This csn be represented in a fraction as:

Kat = 2/5

Sanjeev = 3/5

The amount that each collects will be:

Kat = 2/5 × £255

= 2 × £51

= £102

Sanjeev = 3/5 × £255

= 3 × £51

= £153

6 0
3 years ago
liza's friend marie bought her a dress for 250 euros in france. liza wants to pay marie for it in u.s. dollars. if the foreign e
Rudik [331]
1/ 0.6 = x / 250..1 dollar to 0.6 euros = x dollars to 250 euros
cross multiply
(0.6)(x) = (250)(1)
0.6x = 250
x = 250/0.6
x = 416.67 american dollars
8 0
3 years ago
Read 2 more answers
With a family bowling pass, families can bowl for $4 per game . The pass cost $10 per year. Use equation , a table and a graph t
Klio2033 [76]

Answer:

Part a) a=4g+10 (see the explanation)

Part b) see the explanation

Part c) The graph in the attached figure

Step-by-step explanation:

<u><em>The complete question is</em></u>

With a family bowling pass, families can bowl for $4 per game. The pass costs $10 per year. Use an equation, a table, and a graph to explain the relationship between the total amount of money spent on bowling in a year, a, and the number of games a family plays in a year, g. Part A Use words and an equation to represent this problem. Part B Create a table to show values for g and a. Part C Use the values from your table to draw a graph.

Part A) Use words and an equation to represent this problem

Let

a ----> the total amount of money spent on bowling in a year

g ---> the number of games a family plays in a year

we know that

The linear equation in slope intercept form is equal to

a=mg+b

where

m is the slope or unit rate

b is the a-intercept or initial value

In this problem we have

m=\$4\ per\ game

b=\$10

substitute

a=4g+10

Part b) Create a table to show values for g and a

Assume different values of g and calculate the corresponding values of a

For g=0 ----> a=4(0)+10=\$10

For g=1 ----> a=4(1)+10=\$14

For g=2 ----> a=4(2)+10=\$18

For g=3 ----> a=4(3)+10=\$22

For g=4 ----> a=4(4)+10=\$26

The table is

\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]

Part c) Use the values from your table to draw a graph

we have the ordered pairs

(0,10),(1,14),(2,18),(3,22),(4,26)

Plot the ordered pairs and join them to graph the line

The graph in the attached figure

6 0
3 years ago
I am<br> thinking of a #at least 13
steposvetlana [31]

Answer:

what do u mean

skjfjdkd

3 0
3 years ago
H=4(x+3y)+2 make x the subject
blagie [28]
H = 4(x + 3y) + 2
H = 4x + 12y + 2
H - 12y - 2 = 4x
(H - 12y - 2) / 4 = x or 1/4H - 3y - 1/2 = x

5 0
2 years ago
Read 2 more answers
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