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Rufina [12.5K]
4 years ago
8

Find the value of x.

Mathematics
1 answer:
Naddik [55]4 years ago
3 0

Answer:

x = 27

Step-by-step explanation:

(whole secant) * (external part) = (tangent)^2

(x+48)* 48 = 60^2

(x+48)* 48 = 3600

Divide each side by 48

x+48 =75

Subtract 48 from each side

x = 75-48

x=27

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I think number 9 is b or c, i don't know what 10 is. please help me!!!
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4 years ago
Mark is buying different nuts to make a mixed nut platter to serve at a party. He buys 1.2 kilograms of peanuts, 300 grams of al
Nutka1998 [239]

Answer:

1900

Step-by-step explanation:

1 kg = 1000g

1.2kg = x

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1kg. 1kg

x = 1200 g

1 decagram = 10g

40 decagram = x

<u>1</u><u> </u><u>dg.x</u> = <u>4</u><u>0</u><u>0</u><u> </u><u>dg.g</u>

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without the unit = 1900

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3 years ago
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3 years ago
What is the solution for x in the given equation? The square root of 9x +7 + the square root of 2x = 7
cestrela7 [59]

Answer:

The solution is x =2 for the given equation \sqrt{9x+7} +\sqrt{2x}=7

Step-by-step explanation:

We need to find the solution for x in the given equation.

\sqrt{9x+7} +\sqrt{2x}=7

Solving:

Subtract \sqrt{2x} from both sides

\sqrt{9x+7} =7-\sqrt{2x}

Taking square on both sides

(\sqrt{9x+7})^2 =(7-\sqrt{2x})^2\\Using\,\, (a-b)^2 = a^2-2ab-b^2\\9x+7=(7)^2-2(7)(\sqrt{2x})+(\sqrt{2x})^2\\9x+7=49-14\sqrt{2x}+2x\\9x-2x+7-49=-14\sqrt{2x}\\7x-42=-14\sqrt{2x}\\Taking\,\,square\,\,on\,\,both\,\,sides\\(7x-42)^2=(-14\sqrt{2x})^2\\49x^2-2(7x)(42)+(42)^2= 196(2x)\\49x^2-588x+1764=392x\\49x^2-588x+1764-392x=0\\49x^2-980x+1764=0\\Using \,\,quadratic \,\, equation  \,\,to \,\, find \,\, value \,\, of \,\, x \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a= 49, \, b= -980 \,\,and\,\, c = 1764

Putting values and solving

x=\frac{-(-980)\pm\sqrt{(-980)^2-4(49)(1760)}}{2(49)}\\x=\frac{980\pm\sqrt{614656}}{98}\\Solving\\x=18 \,\, and x =2

Verifying the solution by putting values of x in given equation

Putting x=18

\sqrt{9x+7} +\sqrt{2x}=7\\\sqrt{9(18)+7} +\sqrt{2(18)}=7\\\sqrt{169} +\sqrt{36}=7\\13+6=7\\19\neq 7

So, x=18 is not solution o given equation.

Putting x = 2

\sqrt{9x+7} +\sqrt{2x}=7\\\sqrt{9(2)+7} +\sqrt{2(2)}=7\\\sqrt{25} +\sqrt{4}=7\\5+2=7\\7=7

So, x=2 satisfies the equation

The solution is x =2 for the given equation \sqrt{9x+7} +\sqrt{2x}=7

7 0
3 years ago
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