1. Write an equation in slope-intercept form of the line with the given slope and point: slope = 3 and (1, -2).

1 answer:

3 0

1. The linear equation:
y = m x + b
m = 3
- 2 = 3 · 1 + b
- 2 = 3 + b
b = - 5
Answer: A ) y = 3 x - 5
2. We will solve the system of equations:
12 = - 4 m + b / · ( - 1 )
23 = 7 m + b
----------------------
- 12 = 4 m - b
+
23 = 7 m + b
--------------------
11 = 11 m, m = 1, b = 16
Answer: A ) y = x + 16

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What is the distance between ( 8 , − 3 ) (8,−3)left parenthesis, 8, comma, minus, 3, right parenthesis and ( 4 , − 7 ) (4,−7)lef

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Given Information:

Point 1 = (8, −3)

Point 2 = (4, −7)

Required Information:

Distance between points = d = ?

Answer:

Distance between points = d = √32 = 5.657

Step-by-step explanation:

We are given two points,

(x₁, y₁) = (8, −3)

(x₂, y₂) = (4, −7)

We are asked to find the distance between these two points.

The distance is given by

$d = \sqrt{(x_2 - x_1)^2 +(y_2 - y_1)^2 }$

Substitute the given coordinates into above equation

$d = \sqrt{(x_2 - x_1)^2 +(y_2 - y_1)^2 } \\\\d = \sqrt{(4 - 8)^2 +(-7 - (-3))^2 } \\\\d = \sqrt{(-4)^2 +(-7 +3)^2 } \\\\d = \sqrt{(-4)^2 +(-4)^2 } \\\\d = \sqrt{16 +16 } \\\\d = \sqrt{32} \\\\d = 5.657$

Therefore, the distance between (8, −3) and (4, −7) is 5.657 units.

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