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Damm [24]
3 years ago
14

Choose the sequence that orders the fractions from least to greatest.

Mathematics
1 answer:
kakasveta [241]3 years ago
3 0
The last choice is right
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Explain why please and make sure it is in full detail
Marysya12 [62]

Step-by-step explanation:

well,

(y - 7)² = (y - 7)(y - 7)

remember how to multiply 2 expressions ?

you have to multiply every term of one expression with every term of the other expression and sum the results all up (incl. considering their individual signs, of course).

so, when we do the multiplication, we get

(y - 7)(y - 7) = y×y - 7×y - 7×y + (-7)×(-7) =

= y² - 14y + 49

and that is clearly different to y² - 49

FYI

y² - 49 is the result of

(y - 7)(y + 7)

because

y×y + 7×y - 7×y + (-7)(7) = y² - 49

8 0
3 years ago
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I need help doing the area model
Mars2501 [29]
It is 0.4 so it should look like this

7 0
4 years ago
Please help with math ASAP, will give brainliest!!
ycow [4]

Answer:

45

60

135

150

Step-by-step explanation:

Remember:

1 radian is 57.3 degrees

7 0
3 years ago
For the week , emma had originally selected 8 intervals the interval she put up was not picked up or swapped , nor did she show
NNADVOKAT [17]

Option(C): 85%.

Considering the above info given on Emma's activity, she was also late by 5 minutes for two others intervals. And her technical issue was preventing her from servicing for 45 minutes.

ICAI recently announced the results of the CA final exams for the May session. A total of 6,657 candidates appeared for group I and 63,253 candidates appeared for Group II out of which 14,643 and 13,877 candidates cleared the exam, respectively. The pass percentage recorded for the May session was only around 21 percent.

ca passing % will always stay low as it's a prestigious degree to get. it's a symbol of sheer hard work and dedication. however these days it is an all-time low if u will compare the results of the last 10 attempts. it is because market demand for ca's has gone very low.

Learn more about percentages at

brainly.com/question/843074

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8 0
2 years ago
the set $s = \$ contains the first $50$ positive integers. after the multiples of 2 and the multiples of 3 are removed, how many
Sophie [7]

Clearly, |S| = 50.

Count the multiples of 2 between 1 and 50:

⌊50/2⌋ = ⌊25⌋ = 25

(where ⌊x⌋ denotes the "floor of x", or the largest integer that is smaller than or equal to x; in other words, round <u>down</u> to the nearest integer)

Count the multiples of 3 between 1 and 50:

⌊50/3⌋ ≈ ⌊16.667⌋ = 16

Since LCM(2, 3) = 6, the sets of multiples of 2 and multiples of 3 have some overlap. Count the multiples of 6 between 1 and 50:

⌊50/6⌋ ≈ ⌊8.333⌋ = 8

Then by the inclusion/exclusion principle, we remove from S

25 + 16 - 8 = 33

elements, so that the new set S contains 50 - 33 = 17 elements.

5 0
3 years ago
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