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3 years ago

What is the area of the trapezoid and how do you find it?

Mathematics

2 answers:

seraphim [82]3 years ago

8 0

You can use the formula 2(a+b $2(\frac{a+b}{2} )$
This will get you 161.5 ft

:)

Furkat [3]3 years ago

6 0

A= a+b/2 H Find it by take the sum of its bases, multiply the sum by the height of the trapezoid, and then divide the result by 2.

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What are the real zeros of x^3+4x^2-9x-36

Katyanochek1 [597]

Answer:

$x = -4\\x = -3\\x = 3$

Step-by-step explanation:

To find the real zeros you must match the function to zero and factor the expression.

We have a polynomial of degree 3.

We try to group the terms to perform the factorization

$x ^ 3 + 4x ^ 2-9x-36 = 0\\\\x ^ 2(x + 4) - 9(x + 4) = 0$

Now we take (x + 4) as a common factor

$(x + 4)(x ^ 2 -9) = 0$

If we have an expression of the form $(a ^ 2-b ^ 2)$ we know that this expression is equivalent to:

$(a ^ 2-b ^ 2) = (a + b)(a-b)$

In this case

$a = x\\b = 3$

So:

$(x ^ 2 -9) = (x + 3)(x-3)$

Finally:

$x ^ 3 + 4x ^ 2-9x-36 = (x + 4)(x + 3)(x-3) = 0$

The solutions are:

$x = -4\\x = -3\\x = 3$

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3 years ago

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melomori [17]

A= 3.1 and b= 2.5 hope this helps

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3 years ago

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vagabundo [1.1K]

Answer:

x^2-10x+25

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2 so a=x and b=-5 so the expression is x^2-10x+25

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ElenaW [278]

Answer:

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Step-by-step explanation:

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