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Rus_ich [418]
3 years ago
5

Estimate 78 percent of 20 A. 14 B. 16 C. 19 D. 2

Mathematics
1 answer:
MrRa [10]3 years ago
4 0
B is the answer............
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Find slopes , ill mark brainlist
zepelin [54]

Answer:

\frac{3}{2} or 1\frac{1}{2}

Step-by-step explanation:

We are given a graph and asked to find the slope.

So we can see two coordinate points, one on (0, 3) and (2, 0).

When trying to find slope, we use the method rise over run, which basically means y over x as a fraction, in which you then divide.

So count how many times it'll take for x to get to y, base it off the picture below

Since we see our numbers to be divided are 3 over 2, do the division and you get 1 1/2.

Would this be negative though? No, since the graph is in an increase, not a decrease.

4 0
2 years ago
Algebra I: Quadratics
sertanlavr [38]
The answer id 12 meters.divide -2x^2+20x+48 by 2 to get x alone and then umbrella
3 0
3 years ago
If a physician order is 25% dextrose 1000 mL and all you have is 70% dextrose 1000 mL and 5% dextrose how much 70% dextrose will
miskamm [114]

Answer:

The answer is below

Step-by-step explanation:

Since 1000ml Of Dextrose 25% is needed to be produced from Dextrose 70%. Let us assume that x ml of Dextrose 70% is mixed with a Dextrose 5% to get 1000 ml of Dextrose 25%. Hence:

The amount of Dextrose 5% = 1000 ml - x ml = 1000 - x

25% of 1000 ml = 70% of x + 5% of (1000 - x)

25000 = 70x + 5000 - 5x

Simplifying gives:

65x = 25000 - 5000

65x = 20000

x = 308 ml

Therefore 308 ml of Dextrose 70% was mixed with 692 ml of Dextrose 5% to produce 1000 ml of Dextrose 25%.

7 0
3 years ago
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
2 years ago
How many extraneous solutions does the equation below have? 9 over n squared +1 =n+3 over 4? 0 1 2 3
LenKa [72]
The answer is 0. While the answer for n is approximately 2.384503, there are no EXTRANEOUS solutions. Again, the answer is a.) 0
4 0
3 years ago
Read 2 more answers
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