Hi there!
Here we go:
2x + 1 ≤ 
You need to multiply each side of the equation by 2
4x + 2 ≤ 3(x + 1)
You need to distribute the 3 to the entire parentheses
4x + 2 ≤ 3x + 3
You need to subtract 3x from each side of the equation
x + 2 ≤ 3
You need to subtract 2 from each side of the equation
x ≤ 1
There you go! I really hope this helped, if there's anything just let me know! :)
Answer:
Yes, an arrow can be drawn from 10.3 so the relation is a function.
Step-by-step explanation:
Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.
The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.
In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.
However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.
Answer: odd
Step-by-step explanation:
Given
The graph of a function increases as x increases and decreases as x decreases.
This shows that the degree of the polynomial is odd
for example 
Here, the leading coefficient is positive, and the value of function increases as x increases and vice-versa.
Answer:
Step-by-step explanation:
Given that customers arrat a service window according to a poisson process with an average of 0.2 per minute
= 12 per hour.
a) the probability that the time between two successive arrivals is less than 6 minutes
= For one hour more than 60/6 =10 customers arrive.
P(X>10) = 0.6528
b) Prob that there will be exactly three arrivals during a given 10-minute period
P(x=3) for average 2
= 0.1804
