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tigry1 [53]
4 years ago
11

Determine the radius of convergence of the following power series. Then test the endpoints to determine the interval of converge

nce.Σ (x^2k+1)/(11^k-1)a. The interval of convergence is:________b. The radius of convergence is R:_______

Mathematics
1 answer:
Karolina [17]4 years ago
3 0

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

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BRAINLIESTTT ASAP!!! PLEASE HELP ME :)
Triss [41]

Answer:

Let D represent the average rate of change between 1990 and 1999

D ≈ 33%

Step-by-step explanation:

412+412×(D÷100 )= 549

⇔ 412×(D÷100) = 549 - 412

⇔ 412×(D÷100) = 137

⇔ D÷100 = 137÷412

⇔ D÷100 = 0.332524271845

⇔ D = 33.2524271845.

:)

3 0
4 years ago
Read 2 more answers
The body temperatures of adults are normally distributed with a mean of 98.6degrees° F and a standard deviation of 0.60degrees°
Schach [20]

Answer:

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 98.6, \sigma = 0.6, n = 36, s = \frac{0.6}{\sqrt{36}} = 0.1

If 36 adults are randomly​ selected, find the probability that their mean body temperature is greater than 98.4degrees° F.

This is 1 subtracted by the pvalue of Z when X = 98.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{98.4 - 98.6}{0.1}

Z = -2

Z = -2 has a pvalue of 0.0228

1 - 0.0228 = 0.9772

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

6 0
3 years ago
Please help me with this i beg of u due today
krek1111 [17]

Answer:

35) A. 21.2

46) D. 4/7

30) B. 4.4

42) C. Prism

Step-by-step explanation:

35) see first two attached files. 134.3 - 113.1 = 21.2

46) see third attached file. 4/7 = .5714 ish and 112 pi = 351.59 ish

30) see fourth attached file.

42) prisms are in no way circular so it cant have a circular base when cut

Already did this but may as well get the points haha

4 0
3 years ago
PartB needs to be solved.The table below shows the fourth powers of different numbers:Number (x) 1,-1,3,-3Fourth power of the nu
Makovka662 [10]

Given:

f(x)=875x+750

To find:

The value of f(12).

Explanation:

Substituting x = 12 we get

\begin{gathered} f(12)=875(12)+750 \\ =11250 \end{gathered}

That means,

The total cost for renting a townhouse for 12 months is $11250.

Where f(12) represents the total cost of renting a townhouse for 12 months.

Final answer:

• The value is,

f(12)=11250

• The value f(12) represents the total cost of renting a townhouse for 12 months.

That is, the total cost for 12 months is $11250.

8 0
1 year ago
Find the product 2y^2(3x+5z)
fgiga [73]
2y^2 (3x+5z)
6xy^2 + 10zy^2
8 0
4 years ago
Read 2 more answers
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