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castortr0y [4]
3 years ago
7

What is -8 • 7 + 33 / -11

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
7 0

Hello there!

-8 * 7 + 33 / -11

Explanation:

↓↓↓↓↓↓↓

First you had to multiply by 7.

8*7=56

\frac{33}{-11}=-3

-56-3

Then you subtract by the number.

-56-3=-59

Answer⇒⇒⇒⇒-59

Hope this helps!

Thank you for posting your question at here on Brainly.

Have a great day!

-Charlie

Strike441 [17]3 years ago
3 0

-8 x 7 = -56

33/-11 = -3

-56

+

-03

_______

-59

-59 is your answer!

Hope I helped!

Good Luck!

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Use the laplace transform to solve the given initial-value problem. y' 5y = e4t, y(0) = 2
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The Laplace transform of the given initial-value problem

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<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>

Generally, the equation for the problem is  mathematically given as

&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}

\begin{aligned}&\text { Let } \frac{2 s-7}{(s+5)(s-4)}=\frac{a_{0}}{s-4}+\frac{a_{1}}{s+5} \\&\Rightarrow 2 s-7=a_{0}(s+s)+a_{1}(s-4)\end{aligned}

put $s=-s \Rightarrow a_{1}=\frac{17}{9}$

\begin{aligned}\text { put } s &=4 \Rightarrow a_{0}=\frac{1}{9} \\\Rightarrow \quad y(s) &=\frac{1}{9(s-4)}+\frac{17}{9(s+s)}\end{aligned}

In conclusion, Taking inverse Laplace tranoform

L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

Read more about Laplace tranoform

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