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il63 [147K]
3 years ago
15

Help on #3 I’m so lost :(

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
6 0
The answer is B. -6. First, you multiply everything inside the parenthesis by the 2 that’s on the outside. Now you have 2n + 10 = -2. Subtract the 10 from both sides. You then have 2n = -12. Divide the 2 from the n on both sides in order to isolate your variable. You are left with your answer, n = -6. Hope this helps. :)
stiv31 [10]3 years ago
5 0

Answer: -6

Step-by-step explanation: use the distributive property and distribute the two to the n and 5. that’ll leave you with 2n+10=-2. then you subtract 10 from both sides and get left with 2n=-12. and then to get the exponent by itself, you divide by two on both sides. and then you’re left with n=-6 :)

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defon

Answer:

-2.5

Step-by-step explanation:

-30 + (-15) + (-20) + 55 = -10. Then you divide it by how many numbers there are (4). Which equals - 2.5. If this is wrong, then round up to -3.

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A genetic experiment involving peas yielded one sample of offspring consisting of 420 green peas and 174 yellow peas. Use a 0.01
slavikrds [6]

Answer:

a) z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649  

b) For this case we need to find a critical value that accumulates \alpha/2 of the area on each tail, we know that \alpha=0.01, so then \alpha/2 =0.005, using the normal standard table or excel we see that:

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Step-by-step explanation:

Data given and notation

n=420+174=594 represent the random sample taken

X=174 represent the number of yellow peas

\hat p=\frac{174}{594}=0.293 estimated proportion of yellow peas

p_o=0.23 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of yellow peas is 0.23:  

Null hypothesis:p=0.23  

Alternative hypothesis:p \neq 0.23  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

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b) Critical value

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Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

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zhannawk [14.2K]
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