Answer:
Step-by-step explanation:
4*3^x+1=27+(3^2)^x
(3^2)^x=(3^x)^2
3^x=t
4t+1=27+t^2
t^2-4t+27-1=0
t^2-4t+26=0
delta=4^2-4*1*26=16-84=-68<0
the equation has not real solutions
There is no hard and fast rule to select the class width. It largely depends on our application.However, one thing that should be kept in mind is that the number of classes should neither to be too low nor too high. So keeping this thing in mind, the class width is select.
The range of the data is = Maximum- Minimum = 96 - 11 = 85
10 classes will be most suited for this data.
The class width for each data can be calculated as:
Class Width = Range / Number of Classes = 85/10 = 8.5
Class width is always rounded to nearest next integer. So the class width will be 9 in this case.
So, the best value of class width or interval width for the given data will be 9.
2- and 3- not sure though
1.
Answer B.
2.
Answer B.
3.
Answers A. and C.
After each cut, by observing the graph, the remaining area is 80% of the previous area.
It is given that
Actual area = 100cm²
<h3>What is the percentage?</h3>
The percentage is the value per hundred.
According to the graph,
Area after the first cut =80cm² (80% of the previous are)
Area after the second cut = 64 cm²(80% of 80)
Area after third cut = 51.2 cm²(80% of 64)
So we can observe that area after each cut is 80% of the previous area.
Therefore, after each cut, the remaining area is 80% of the previous area.
to get more about percentage visit:
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