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4 years ago

What times 2 =121 example 2x2=4

Mathematics

2 answers:

bearhunter [10]4 years ago

6 0

Answer:

Do you mean 11*11=121

Step-by-step explanation:

11 multiplied by 11

Sergeeva-Olga [200]4 years ago

4 0

Answer:

60.5

Step-by-step explanation:

All you need to do is divide 121 and 2. When you do so you world get 60.5.

To check, 60.5 times 2 is 121.

Hope this helped!

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Find the inverse of y=-3x+6

mihalych1998 [28]

Answer:

y = (x – 6) / -3 = [2 – x/3]

Step-by-step explanation:

y = f(x) = -3x + 6

f⁻¹(x) → x = -3y + 6 → (x – 6) / -3 → x / -3 + -6/-3 → -x / 3 + 2 → 2 – x/3

5 0

3 years ago

\lim _{x\to 0}\left(\frac{2x\ln \left(1+3x\right)+\sin \left(x\right)\tan \left(3x\right)-2x^3}{1-\cos \left(3x\right)}\right)

Vinvika [58]

$\displaystyle \lim_{x\to 0}\left(\frac{2x\ln \left(1+3x\right)+\sin \left(x\right)\tan \left(3x\right)-2x^3}{1-\cos \left(3x\right)}\right)$

Both the numerator and denominator approach 0, so this is a candidate for applying L'Hopital's rule. Doing so gives

$\displaystyle \lim_{x\to 0}\left(2\ln(1+3x)+\dfrac{6x}{1+3x}+\cos(x)\tan(3x)+3\sin(x)\sec^2(x)-6x^2}{3\sin(3x)}\right)$

This again gives an indeterminate form 0/0, but no need to use L'Hopital's rule again just yet. Split up the limit as

$\displaystyle \lim_{x\to0}\frac{2\ln(1+3x)}{3\sin(3x)} + \lim_{x\to0}\frac{6x}{3(1+3x)\sin(3x)} \\\\ + \lim_{x\to0}\frac{\cos(x)\tan(3x)}{3\sin(3x)} + \lim_{x\to0}\frac{3\sin(x)\sec^2(x)}{3\sin(3x)} \\\\ - \lim_{x\to0}\frac{6x^2}{3\sin(3x)}$

Now recall two well-known limits:

$\displaystyle \lim_{x\to0}\frac{\sin(ax)}{ax}=1\text{ if }a\neq0 \\\\ \lim_{x\to0}\frac{\ln(1+ax)}{ax}=1\text{ if }a\neq0$

Compute each remaining limit:

$\displaystyle \lim_{x\to0}\frac{2\ln(1+3x)}{3\sin(3x)} = \frac23 \times \lim_{x\to0}\frac{\ln(1+3x)}{3x} \times \lim_{x\to0}\frac{3x}{\sin(3x)} = \frac23$

$\displaystyle \lim_{x\to0}\frac{6x}{3(1+3x)\sin(3x)} = \frac23 \times \lim_{x\to0}\frac{3x}{\sin(3x)} \times \lim_{x\to0}\frac{1}{1+3x} = \frac23$

$\displaystyle \lim_{x\to0}\frac{\cos(x)\tan(3x)}{3\sin(3x)} = \frac13 \times \lim_{x\to0}\frac{\cos(x)}{\cos(3x)} = \frac13$

$\displaystyle \lim_{x\to0}\frac{3\sin(x)\sec^2(x)}{3\sin(3x)} = \frac13 \times \lim_{x\to0}\frac{\sin(x)}x \times \lim_{x\to0}\frac{3x}{\sin(3x)} \times \lim_{x\to0}\sec^2(x) = \frac13$

$\displaystyle \lim_{x\to0}\frac{6x^2}{3\sin(3x)} = \frac23 \times \lim_{x\to0}x \times \lim_{x\to0}\frac{3x}{\sin(3x)} \times \lim_{x\to0}x = 0$

So, the original limit has a value of

2/3 + 2/3 + 1/3 + 1/3 - 0 = 2

6 0

3 years ago

IDK how to deal with big boy numbers! SOS

qaws [65]

Answer:

SOSOSOSOSOSOSOSOSOSOS

Step-by-step explanation:

WE HAVE A 911 HERE THERE SEEMS TO BE NUMBERS AT HOSTAGE WEE WOO WEE WOO

4 0

3 years ago

Read 2 more answers

A cuboid has a square base of side x cm. The volume of the cuboid is V cm^3 and the height is h cm.

Lemur [1.5K]

You will need the formula for finding the volume of a rectangular prism (cuboid).
V = l x w x h

1. V = x^2 x h

2. To solve for x, you will substitute in the information you know.

150 = x^2 x 24
Divide both sides by 24 to get

6.25= x^2
The square root of 6.25 is 2.5.

x = 2.5 cm

7 0

3 years ago

X^2+_x+_=0<br> Please help need to pass this class

snow_tiger [21]

Answer:
x^2+0x+(-x^2)=0

Explanation:
x^2+0x+(-x^2)=0
Anything multiplied by 0 is equal to 0
x^2+0+(-x^2)=0
x^2+(-x^2)=0
A positive and a negative makes a negative
x^2-x^2=0
0=0

For these types of problems, play around with multiplying by 0 and adding negatives.

I hope this helps! Please comment if you have any questions.

7 0

3 years ago