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Rudiy27
2 years ago
14

A box contains 6 red marbles, 4 green marbles, 3 blue marbles, and 2 yellow marbles. If one marble is chosen at random, what is

the probability that it will be blue?
Mathematics
1 answer:
Setler [38]2 years ago
4 0

Answer:

1/5

Step-by-step explanation:

# blue/total # of marbles

3/15 now   simplify by dividing both top and bottom by 3

1/5

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Answer:

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Step-by-step explanation:

This is a uniform distribution with parameters a = 1.00 and b =5.00. With these conditions, the following probability distribution functions can be applied:

P(X \leq x)=\frac{x-a}{b-a}=\frac{x-1.00}{5.00-1.00}\\P(X \leq x) = \frac{x-1}{4}\\P(X \geq x) = 1- P(X \leq x) \\P(X \geq x)=1- \frac{x-1}{4}

Therefore, the probability that X ≥ 4:00 p.m. is given by

P(X \geq 4)=1- \frac{4-1}{4}\\P(X \geq 4)=0.25=25\%

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Step-by-step explanation:

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Find the distance between the points (0, 10) and (–9, 1).
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\\ \sf\longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

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