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3 years ago

Which terms accurately classify this triangle?

Mathematics

2 answers:

Andrei [34K]3 years ago

5 0

Its right and isosceles because the little squares means that's it's a right triangle. And the lines means it's identical which an isosceles has two identical lines

Norma-Jean [14]3 years ago

5 0

A) right and D) isosceles

You might be interested in

A is the smallest two digit whole number; "b" is the sum of prime numbers up to 10. what is a b?

Natasha2012 [34]

Whole numbers are like 0,1,2,3,4,5...
the smallest one is 10

prime numbers
I do not accept 1 as a prime number, if you agree, go to AAAAAAAAA
if you do think it's a prime number, go to BBBBBBB

AAAAAAA
2,3,5,7
2+3+5+7=17
a+b=10+17=27

BBBBBBBBBBB
1,2,3,5,7
1+2+3+5+7=18
a+b=10+18=28

if you do not think a is a prime number, then the answer is 27
if you do think 1 is prime number then the answer is 28

5 0

3 years ago

Read 2 more answers

G. r. a. p. h. 24x-6y=18.

FinnZ [79.3K]

24x−6y=18 Step 1: Add 6y to both sides. 24x−6y+6y=18+6y24x=6y+18

Step 2: Divide both sides by 24.24x24=6y+1824x=14y+34

Answer: x=14y+34

6 0

3 years ago

3. Show how √5 can be represented on the number line.

asambeis [7]

Answer:

Take a line segment AB = 2 units (consider 1 unit = 2 cm) on x-axis.

Draw a perpendicular on B and construct a line BC = 1 unit length.

Join AC which will be √5 (Pythagoras theorem). Take A as center, and AC as radius draw an which cuts the x-axis at point E.

The line segment AC represents √5 unit

3 0

3 years ago

An HR director numbered employees 1 through 50 for an extra vacation day contest. What is the probability that the HR director w

forsale [732]

Answer:

The probability that the HR director will select an employee who is not a multiple of 13 is $\frac{47}{50}$

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- The probability of an event is the measure of the chance that the

event will occur

- The probability of an event A is the number of ways that event A can

occur divided by the total number of possible outcomes

- If P(A) is the probability of event A, is the probability that the event A

does not occur is 1 - P(A)

* <em>Lets solve the problem</em>

- An HR director numbered employees 1 through 50 for an extra

vacation day contest

∴ There are 50 employees

- The HR director will select an employee

- We need to find the probability of select an employees who is not

multiple of 13

* At first lets find the multiples of 13

∵ 13 × 1 = 13

∵ 13 × 2 = 26

∵ 13 × 3 = 39

∴ The multiples of 13 from 1 to 50 are 13 , 26 , 39

∵ There are 3 multiples of 13

∵ There are 50 numbers

∵ Probability of multiple of 13 = $\frac{3}{50}$

∵ Probability of not multiple of 13 = 1 - P(multiple of 13)

∴ Probability of not multiple of 13 = $1-\frac{3}{50}$

∴ Probability of not multiple of 13 = $\frac{47}{50}$

* The probability that the HR director will select an employee who is

not a multiple of 13 is $\frac{47}{50}$

4 0

3 years ago

An exit poll in an election is a survey taken of voters just after they have voted. One major use of exit polls has been so that

3241004551 [841]

Answer:

P(A) = 0.39

Step-by-step explanation:

We are given;

P(W|A) = 0.7

P(W|A^c ) = 0.3

We are told that 60% of the respondents said they voted for A. Thus;

P(A|W) = 60% = 0.6

Now, using the principle of drawing lots, we can be able to find the probability of the event that they are willing to participate in the exit poll which is P(W).

Thus;

P(W) = [P(W|A) × P(A)] +[P(W∣A^c) × P(A^c)]

Now, P(A^c) can be expressed as 1 - P(A)

Thus, we now have;

P(W) = [P(W|A) × P(A)] + [P(W∣A^c) × (1 - P(A)]

Plugging in the relevant values gives;

P(W) = 0.7P(A) + 0.3(1 - P(A))

P(W) = 0.7P(A) + 0.3 - 0.3P(A)

P(W) = 0.3 + 0.4P(A)

Now,using Baye's theorem, we can find an expression for P(A|W)

Thus;

P(A|W) = [P(A ∩ W)]/P(W)

This can be further expressed as;

P(A|W) = [P(A) × P(W|A)]/P(W)

Plugging in relevant values, we have;

0.6 = 0.7P(A)/(0.3 + 0.4P(A))

Cross multiply to get;

0.6(0.3 + 0.4P(A)) = 0.7P(A)

0.18 + 0.24P(A) = 0.7P(A)

0.18 = 0.7P(A) - 0.24P(A)

0.46P(A) = 0.18

P(A) = 0.18/0.46

P(A) = 0.39

7 0

3 years ago