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Ilia_Sergeevich [38]
4 years ago
10

What two benefits do you receive from owning stock?

Business
1 answer:
Helga [31]4 years ago
8 0
A benefit is that it. gives you control over your finance.
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What constitutes relevant, valid and reliable data? ​
harina [27]

Answer:

Reliability and validity are concepts used to evaluate the quality of research. They indicate how well a method, technique or test measures something. Reliability is about the consistency of a measure, and validity is about the accuracy of a measure.

Explanation:

3 0
3 years ago
Strong, Inc., bundles two kinds of service activities into a single $6,000 fixed-price contract, yielding two distinct performan
frozen [14]

Answer:

the revenue recognized is $3,750

Explanation:

The computation of the revenue that recognized by the end of the second month is given below:

= $6,000 ÷ $6,400 × $3,200 + $6,000 ÷ $6,400 × $3,200 × 2 months ÷ 8 months

= $3,750

The $6,400 comes from

= $3,200 + $3,200

= $6,400

Hence, the revenue recognized is $3,750

3 0
3 years ago
When a person places him or herself in a position in which he or she might be exploited by another, and does so willingly with t
dalvyx [7]

Answer:

vulnerability

Explanation:

When an individual is vulnerable, it means that he/she is being exposed to the possibility of being physically or emotionally wounded.

Usually individuals place themselves in a position of vulnerability in a relationship when they have a very high degree of affection for the other person and assume the risk of being emotionally exposed.

4 0
3 years ago
The united states has an unemployment compensation program that provides income for those out of work. in this case, unemploymen
mafiozo [28]
Is it collecting unemployment check.
3 0
3 years ago
A metal sphere of radius 15 cm has a net charge of 3.0 $ 10#8 C. (a) What is the electric field at the sphere’s surface? (b) If
denis-greek [22]

Answer:

E = 1.20 × 10^{4} N/C

V = 1800 V

x = 0.058 m

Explanation:

given data

radius = 15 cm

net charge = 3 × 10^{-8} C

electric potential decreased = 500 V

solution

we get here electric field at the sphere’s surface that is

electric field at the sphere’s surface E  =  \frac{q}{4\pi \epsilon _o R^2}   ............1

put here value

electric field at the sphere’s surface E  = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15^2}    

E = 1.20 × 10^{4} N/C

and

potential on surface of sphere is

V =  \frac{q}{4\pi \epsilon _o R} ................2

V = \frac{3\times 10^{-8}\times 8.99\times 10^9}{ 0.15}  

V = 1800 V

and

now we get distance that is x

and we know here

ΔV = V(x) - V   ..............3

substitute here value

-500V = \frac{q}{4\pi \epsilon _o } \times (\frac{1}{R+x} - \frac{1}{R})

-500 V = {3\times 10^{-8}\times 8.99\times 10^9} \times (\frac{1}{0.15+x} - \frac{1}{0.15})

solve it we get x

x = 0.058 m

3 0
3 years ago
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