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4 years ago

How many flowers, spaced every 4 in., are needed to surround a circular garden with a 100-ft radius? use 3.14

Mathematics

1 answer:

IRINA_888 [86]4 years ago

7 0

Answer:

Step-by-step explanation:

Let us first calculate the circumference of the circular of the circular garden

$C= 2\pi r$

Given

r= 100

$C= 2*3.142*100\\C= 628.4 ft$

Since the desired space between flowers is 4ft

Then the flowers needed for the garden is $\frac{628.4}{4} = 157.1$

Approximately the number of flowers is 157

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Before we can make the mashed potatoes, we need to boil some water. The water starts out at room temperature, 70° F, and increas

Karolina [17]

Answer:

Part a) $y=50t+70$

Part b) $t=2.84\ min$

Step-by-step explanation:

Part a) Create a linear equation

Let

t ----> the time in minutes

y ---> the temperature in °F

we know that

The linear equation in slope intercept form is equal to

$y=mt+b$

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value of the linear equation

In this problem we have

The slope m is equal to

$m=50\° F\ per\ minute$

The y-intercept is

$b=70\° F$

substitute

$y=50t+70$

Part b) How many minutes until the water boils at 212° F?

For y=212° F

substitute in the linear equation and solve for t

$212=50t+70$

$50t=212-70$

$50t=142$

$t=2.84\ min$

6 0

3 years ago

What is the solution of x^2+x-6/x-7<0 PLEASE HELP ME :( (it’s not the 2nd one i already tried it)

blsea [12.9K]

Answer:

the first one $\:x\le \:-3\quad \mathrm{or}\quad \:2\le \:x$

Step-by-step explanation:

Factor $x^2+x-6$ :

Break the expression into groups

$\left(x^2-2x\right)+\left(3x-6\right)$

$\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-2x\mathrm{:\quad}$

$x\left(x-2\right)$

$\mathrm{Factor\:out\:}3\mathrm{\:from\:}3x-6\mathrm{:\quad}$

$3\left(x-2\right)$

$x\left(x-2\right)+3\left(x-2\right)$

$\mathrm{Factor\:out\:common\:term\:}x-2$

$\left(x-2\right)\left(x+3\right)$

$\frac{\left(x-2\right)\left(x+3\right)}{x-7}\\$

$\frac{\left(x-2\right)\left(x+3\right)}{x-7}\le \:0$

$\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{\left(x-2\right)\left(x+3\right)}{x-7}$

$\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0$

$x$

Merge Overlapping Intervals

$x\le \:-3\quad \mathrm{or}\quad \:2\le \:x$

6 0

3 years ago

Need help with 12 and 13

EastWind [94]

Answer:

12: 7 13: 49

Step-by-step explanation:

35 divided by 5 is 7 so you would get the answer of 6 for 12

7x7 is 49

6 0

4 years ago

: Use The TI Calculator To Answer The Question. Find The Probability That A Z-score Will Be Between 0.7 And 1.4. A) 0.242 O B) 0

ZanzabumX [31]

Answer:

$P(0.7$

And we can find this probability with the following difference:

$P(0.7$

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

$P(0.7$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

For this case we want to find this probability:

$P(0.7$

And we can find this probability with the following difference:

$P(0.7$

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

$P(0.7$

3 0

3 years ago

Read 2 more answers

The age distribution of students at a community college is given below. Age (years) Number of students (f) Under 21 2890 21-24 2

Soloha48 [4]

Answer:

Are the events A and B disjoint? Yes

Step-by-step explanation:

Disjoint events are those events that cannot occur at the same time, i.e. for events X and Y to be disjoint, $P(X\cap Y)=0$ .

The event A is defined as the number of students whose age is at most 32.

And event B is defined as the number of students whose age is at least 37.

The events A and B are disjoint events.

The sample space for event A consists of all the students of age group (under 21), (21 - 24), (25 - 28) and (29 - 32).

Whereas the sample space for event B consists of all the students of age group (33 - 36), (37 - 40) and (Over 40).

The sample space for the intersection of these two events is:

Sample space of (A ∩ B) = 0

As there are no common terms in both the sample.

Hence proved, events A  and B are disjoint.

3 0

4 years ago