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4 years ago

15

Need help with 12 and 13

1 answer:

EastWind [94]4 years ago

6 0

Answer:

12: 7 13: 49

Step-by-step explanation:

35 divided by 5 is 7 so you would get the answer of 6 for 12

7x7 is 49

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The volume of a certain right circular cylinder is 16. A larger circular cylinder has radius 25% greater and height 50% greater

san4es73 [151]

Answer:

$V_2 = 37.5$

Step-by-step explanation:

Given

$Volume = 16$

Represent the height of the smaller cylinder with h and its radius with r.

The height (H) of the larger cylinder is

$H = h + 50\% * h$

And the radius (R) is;

$R = r + 25\% * r$

Required

Determine the volume of the larger cylinder

Volume of the smaller cylinder is:

$V_1 = \pi r^2h$

Substitute 16 for V1

$16 = \pi r^2h$

While the volume of the larger cylinder is:

$V_2 = \pi R^2H$

We have that:

$H = h + 50\% * h$ and $R = r + 25\% * r$

--------------------------------------------------------------------------------------------------------------

Simplify both expressions

$H = h + 50\% * h$

$H = h + 0.50*h$

$H = h + 0.50h$

$H = 1.50h$

$R = r + 25\% * r$

$R = r + 0.25*r$

$R = r + 0.25r$

$R = 1.25r$

--------------------------------------------------------------------------------------------------------------

Substitute values for R and H in $V_2 = \pi R^2H$

$V_2 = \pi * (1.25r)^2 * 1.50h$

$V_2 = \pi * 1.5625r^2 * 1.50h$

Collect Like Terms

$V_2 = 1.50 * 1.5625* \pi*r^2 * h$

$V_2 = 2.34375* \pi*r^2 * h$

$V_2 = 2.34375* \pi r^2h$

Recall that: $16 = \pi r^2h$

$V_2 = 2.34375* 16$

$V_2 = 37.5$

<em>Hence, the volume of the larger cylinder is 37.5</em>

8 0

3 years ago

jolli1 [7]

Answer:

Part a) $114.3\ yd^{2}$

Part b) $49.5\ yd^{2}$

Step-by-step explanation:

Part a) we know that

The area of the shaded figure is equal to the area of semicircle plus the area of a triangle

<em>Find the area of semicircle</em>

The area of a semicircle is equal to

$A=\frac{1}{2}\pi r^{2}$

we have

$r=5\ yd$

substitute

$A=\frac{1}{2}\pi (5)^{2}=12.5 \pi\ yd^{2}$

<em>Find the area of triangle</em>

The area of the triangle is equal to

$A=\frac{1}{2}(b)(h)$

we have

$b=15\ yd$

$h=5(2)=10\ yd$ -----> the height of triangle is equal to the diameter of semicircle

substitute

$A=\frac{1}{2}(15)(10)=75\ yd^{2}$

<em>Find the area of the shaded figure</em>

$12.5 \pi\ yd^{2}+75\ yd^{2}=(12.5 \pi+75)\ yd^{2}$

assume

$\pi=3.14$

$(12.5(3.14)+75)=114.3\ yd^{2}$

Part b) we know that

The area of the shaded figure is equal to the area of the triangle minus the area of the circle

<em>Find the area of the circle</em>

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=5\ yd$

substitute

$A=\pi (5)^{2}=25 \pi\ yd^{2}$

<em>Find the area of triangle</em>

The area of the triangle is equal to

$A=\frac{1}{2}(b)(h)$

we have

$b=16\ yd$

$h=16\ yd$

substitute

$A=\frac{1}{2}(16)(16)=128\ yd^{2}$

<em>Find the area of the shaded figure</em>

$128\ yd^{2}-25 \pi\ yd^{2}=(128-25 \pi)\ yd^{2}$

assume

$\pi=3.14$

$(128-25(3.14))=49.5\ yd^{2}$

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3 years ago

After taking 4 pieces of fruit out of a bag, 12 pieces of fruit remained. How

k0ka [10]

There was 16 pieces of fruit

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What are the slope and y-intercept of the linear function<br> graphed to the left?

laila [671]

Answer:

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Step-by-step explanation:

The line crosses through the y-axis at 1

By counting, the line goes down one and over two

The line has a downward slope resulting in a negative slope

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Select another format for the following Exponential Expression. 6−3

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The cube root of 6^9

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